我正在为我的Web应用程序实现azure，并尝试通过以下openId connect教程获取访问令牌
当我请求获取访问令牌时，我总是得到错误的请求400
请求获取访问令牌：
POST / {tenant} / oauth2 / token HTTP / 1.1
主持人：https://login.microsoftonline.com
内容类型：application / x-www-form-urlencoded
grant_type = authorization_code
＆CLIENT_ID = 2d4d11a2-f814-46a7-890a-274a72a7309e
＆代码= AwABAAAAvPM1KaPl .......
＆Redcrinter =隐藏％A %% F％Avalanche％Avimeb％F
＆资源= HTTPS％3A％2F％2Fservice.contoso.com％2F
＆client_secret = P @ ssw0rd
这是我的代码：
public static String post( String endpoint,
Map<String, String> params) {//YD
StringBuffer paramString = new StringBuffer("");
//if(!Utilities.checkInternetConnection(context)){
// return XMLHandler.getXMLForErrorCode(context, JSONHandler.ERROR_CODE_INTERNET_CONNECTION);
//}
Iterator<Entry<String, String>> iterator = params.entrySet().iterator();
StringBuffer tempBuffer = new StringBuffer("");
String paramval;
while (iterator.hasNext()) {
Entry<String, String> param = iterator.next();
if (param != null) {
if (paramString.length() > 0) {
paramString.append("&");
}
System.out.println( "post key : " + param.getKey());
String value;
try {
paramval = param.getValue();
if(paramval!=null)
value = URLEncoder.encode(paramval, "UTF-8");
else
value = "";
} catch (UnsupportedEncodingException e) {
value = "";
e.printStackTrace();
}
paramString.append(param.getKey()).append("=")
.append(value);
}
}
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(endpoint);
String data = "";
try {
// Add your data
// httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs))
//httppost.addHeader("Host", host);
httppost.addHeader("Content-Type",
"application/x-www-form-urlencoded");
if (!paramString.equals("")) {
if (tempBuffer.length() > 0) {
data = data + tempBuffer.toString();
}
data = data + paramString.toString();
if (data.endsWith("&")) {
data = data.substring(0, data.length() - 1);
}
httppost.setEntity(new ByteArrayEntity(data.getBytes()));
}
System.out.println( "post Stringbuffer : " + data);
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
int statuscode = response.getStatusLine().getStatusCode();
System.out.println("Response code : " + statuscode);
if (statuscode != 200) {
return null;
}
HttpEntity entity = response.getEntity();
InputStream in = null;
if (entity != null) {
in = entity.getContent();
}
if (in != null) {
StringBuilder builder = new StringBuilder();
String line;
try {
BufferedReader reader = new BufferedReader(
new InputStreamReader(in, "UTF-8"));
while ((line = reader.readLine()) != null) {
builder.append(line);
}
} finally {
in.close();
}
String response2 = builder.toString();
System.out.println("response :" + response2);
retrycount = 0;
return response2;
}
}
catch(UnknownHostException e){
e.printStackTrace();
return null;
}
catch (EOFException eof) {
if (retrycount < max_retry) {
eof.printStackTrace();
post( endpoint, params);
retrycount = 1;
}
} catch (Throwable th) {
throw new IOException("Error in posting :" + th.getMessage());
}
retrycount = 0;
return null;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
请在这件事上给予我帮助
提前致谢
您是否确保传递给/ token的重定向uri与您传递给/授权的重定向相同
我相信，如果您可以使用Postman工具测试当前客户端ID，密码和范围的OAuth验证代码流，以排除错误配置，将会有所帮助。
请参阅以下代码以请求AuthorizationCode。
public static void getAuthorizationCode() throws IOException {
String encoding = "UTF-8";
String params = "client_id=" + clientId
+ "&response_type=" + reponseType
+ "&redirect_uri=http%3A%2F%2Flocalhost%2Fmyapp%2F"
+ "&response_mode=query"
+ "&resource=https%3A%2F%2Fgraph.windows.net"
+ "&state=12345";
String path = "https://login.microsoftonline.com/" + tenantId + "/oauth2/authorize";
byte[] data = params.getBytes(encoding);
URL url = new URL(path);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Length", String.valueOf(data.length));
conn.setConnectTimeout(5 * 1000);
OutputStream outStream = conn.getOutputStream();
outStream.write(data);
outStream.flush();
outStream.close();
System.out.println(conn.getResponseCode());
System.out.println(conn.getResponseMessage());
BufferedReader br = null;
if (conn.getResponseCode() != 200) {
br = new BufferedReader(new InputStreamReader((conn.getErrorStream())));
} else {
br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
}
System.out.println("Response body : " + br.readLine());
}
然后你可以使用你得到的access token获得AuthorizationCode并使用下面的代码获取刷新代码。
public static void getToken(String refreshToken) throws IOException {
String encoding = "UTF-8";
String params = "client_id=" + clientId + "&refresh_token=" + refreshToken
+ "&grant_type=refresh_token&resource=https%3A%2F%2Fgraph.windows.net";
String path = "https://login.microsoftonline.com/" + tenantId + "/oauth2/token";
byte[] data = params.getBytes(encoding);
URL url = new URL(path);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Length", String.valueOf(data.length));
conn.setConnectTimeout(5 * 1000);
OutputStream outStream = conn.getOutputStream();
outStream.write(data);
outStream.flush();
outStream.close();
System.out.println(conn.getResponseCode());
System.out.println(conn.getResponseMessage());
BufferedReader br = null;
if (conn.getResponseCode() != 200) {
br = new BufferedReader(new InputStreamReader((conn.getErrorStream())));
} else {
br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
}
System.out.println("Response body : " + br.readLine());
}
希望它能帮到你。