ifstream不会从文件中读取值

问题描述 投票:0回答:1

我正在制作一个可以处理点和文件的程序。我没有警告或错误,但仍然无法正常工作。我认为问题出在ifstream,导致ofstream运作良好,并将输入的值放入文件中。

我得到的输出看起来像这样

Please enter seven (x,y) pairs:
//here the seven pairs are entered

These are your points: 
//(...,...)x7 with the values

These are the points read from the file: 
//and the program ends and returns 0

我希望有人可以帮助我。这是我的代码。

#include <iostream>
#include "std_lib_facilities.h"

using namespace std;

struct Point{
    float x;
    float y;
};

istream& operator>>(istream& is, Point& p)
{
    return is >> p.x >> p.y;
}

ostream& operator<<(ostream& os, Point& p)
{
    return os << '(' << p.x << ',' << p.y << ')';
}

void f() {
    vector<Point> original_points;
    cout << "Please enter seven (x,y) pairs: " << endl;
    for (Point p; original_points.size() < 7;) {
        cin >> p;
        original_points.push_back(p);
    }
    cout << endl;
    cout << "These are your points: " << endl;
    for (int i=0; i < 7; i++) {
        cout << original_points[i] << endl;
    }
    string name = "mydata.txt";
    ofstream ost {name};
    if (!ost) error("can't open output file", name);
    for (Point p : original_points) {
        ost << '(' << p.x << ',' << p.y << ')' << endl;
    }
    ost.close();
    ifstream ist{name};
    if (!ist) error("can't open input file", name);
    vector<Point> processed_points;
    for (Point p; ist >> p;) {
        processed_points.push_back(p);
    }
    cout << endl;
    cout << "These are the points read from the file: " << endl;
    for (int i=1; i <= processed_points.size(); i++) {
        cout << processed_points[i] << endl;
    }
}

int main()
{
    f();
    return 0;
}
c++ iostream ifstream
1个回答
2
投票

您输出方括号和逗号,但不使用它们,因此您的第一次读取操作将失败。试试:

istream& operator>>(istream& is, Point& p)
{
    char open;
    char close;
    char comma;
    is >> open >> p.x >> comma >> p.y >> close;
    if (open != '(' || close != ')' || comma != ',')
    {
      is.setstate(std::ios_base::failbit);
    }
    return is;
}

您的程序也会由于超出向量的范围而最终崩溃,您正在使用从1length的索引,向量是0索引的,因此应从0到[C0 ]:

length-1

或仅使用基于范围的循环:

for (int i = 0; i < processed_points.size(); i++) {
    cout << processed_points[i] << endl;
}
© www.soinside.com 2019 - 2024. All rights reserved.