如何获取python以添加和划分多个变量？

Question

问候python程序员。我正在建立一个树莓派项目，该项目旨在在我的花园中使用湿度传感器。我设计的程序可以读取30秒钟的读数，然后将它们平均为一个数字。它使用四个传感器并在python3.5上运行，并且所有传感器都能正常工作，但是让python进行数学运算来平均输入时遇到了问题。我认为它正在添加变量，但似乎并没有将它们分开。这是代码：

TEST_SOIL()
        outpuT = str(output)
        print("Moisture:", outpuT)
        GPIO.output(buzzer,GPIO.HIGH)
        sleep(0.1) # Delay in seconds
        GPIO.output(buzzer,GPIO.LOW)
        sleep(0.1)
        GPIO.output(buzzer,GPIO.HIGH)
        sleep(0.1) # Delay in seconds
        GPIO.output(buzzer,GPIO.LOW)
        print("TESTING SOIL")
        o1 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o2 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o3 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o4 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o5 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o6 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o7 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o8 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o9 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o10 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o11 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o12 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o13 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o14 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o15 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o16 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o17 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o18 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o19 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o20 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o21 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o22 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o23 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o24 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o25 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o26 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o27 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o28 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o29 = (output + output2 + output3 + output4/4)
        sleep(1)
        TEST_SOIL()
        o30 = (output + output2 + output3 + output4/4)
        sleep(1)
        o = (o1 + o2 + o3 + o4 + o5 + o6 + o7 + o8 + o9 + o10 + o11 + o12 + o13 + o14 + o15 + o16 + o17 + o18 + o19 + o20 + o21 + o22 + o23 + o24 + o25 + o26 + o27 + o28 + o29 + o30)
        o = (o/30) 

[如果有人想知道“ TEST_SOIL（）”是什么，那是我在程序前面创建的我自己的函数。它在这里定义：

def TEST_SOIL():
   output = analogInput(0) # Reading from CH0
   output = interp(output, [0, 1023], [100, 0])
   output = int(output)
   output = (output - 12.5)
   output2 = analogInput(1) # Reading from CH0
   output2 = interp(output2, [1, 1023], [100, 1])
   output2 = int(output2)
   output2 = (output2 - 12.5)
   output3 = analogInput(2) # Reading from CH0
   output3 = interp(output3, [2, 1023], [100, 2])
   output3 = int(output3)
   output3 = (output3 - 12.5)
   output4 = analogInput(3) # Reading from CH0
   output4 = interp(output4, [3, 1023], [100, 3])
   output4 = int(output4)
   output4 = (output4 - 12.5)

我需要提醒一下，此代码还控制了一个小型蜂鸣器，以消除与“ GPIO.output（buzzer，high / low）”文本的任何混淆。如果有人可以告诉我如何解决此代码，那将是很棒的。：）

Answer 1

我有点自由地重构了您的代码。

我认为这4种不同的模拟读数必须保持原样，并且不要碰它们，否则……

• [test_soil现在返回读数的4元组。
• [average_output()将所有可迭代的数字求平均。
• [beep()发出蜂鸣声。
• [main]在循环中调用上述位，将值收集到一个数组中，然后对其求平均。

def TEST_SOIL():
    output = analogInput(0)  # Reading from CH0
    output = interp(output, [0, 1023], [100, 0])
    output = int(output)
    output = output - 12.5
    output2 = analogInput(1)  # Reading from CH0
    output2 = interp(output2, [1, 1023], [100, 1])
    output2 = int(output2)
    output2 = output2 - 12.5
    output3 = analogInput(2)  # Reading from CH0
    output3 = interp(output3, [2, 1023], [100, 2])
    output3 = int(output3)
    output3 = output3 - 12.5
    output4 = analogInput(3)  # Reading from CH0
    output4 = interp(output4, [3, 1023], [100, 3])
    output4 = int(output4)
    output4 = output4 - 12.5
    return (output, output2, output3, output4)


def average_output(o):
    return sum(o) / len(o)


def beep():
    GPIO.output(buzzer, GPIO.HIGH)
    sleep(0.1)  # Delay in seconds
    GPIO.output(buzzer, GPIO.LOW)


def main():
    ao = average_output(TEST_SOIL())
    print("Initial Moisture:", ao)
    beep()
    beep()
    print("TESTING SOIL")
    values = []
    for x in range(30):
        values.append(average_output(TEST_SOIL()))
        sleep(1)
    final_average = average_output(values)
    print("Final Moisture:", final_average )

Answer 2

将(output + output2 + output3 + output4/4)更改为(output + output2 + output3 + output4)/4

您的代码首先将最后一个变量（ouotput4）除以四，然后将它们加在一起。

（（编辑：忘记了列表没有平均功能。对不起。您可以将sum()用于某些列表，然后将其除以该列表的len()）] >>

Answer 3

这可能能够修复您的代码并对其进行整理您可以使用for循环来简化工作，而不必再次编写相同的内容