我创建了使用NodeJS和Busboy在Firebase上载单个图像的函数,该函数返回图像url。允许的图像扩展名只有.jpg
和.png
。它将生成随机文件名并使用storageBucket
创建文件路径。
但是,我正在努力重构此功能,因此我可以上传多张图像。我尝试了几次,但没有运气。如果所有图像均已成功上传,则它应返回图像URL的数组。
这里是我上传单张图片的功能:
const { admin, db } = require("./admin");
const config = require("./config");
exports.uploadImage = (req, res, url, folder) => {
const BusBoy = require("busboy");
const path = require("path");
const os = require("os");
const fs = require("fs");
const busboy = new BusBoy({ headers: req.headers });
let imageFileName;
let imageToBeUploaded = {};
busboy.on("file", (fieldname, file, filename, encoding, mimetype) => {
if (mimetype !== "image/jpeg" && mimetype !== "image/png") {
return res
.status(400)
.json({ error: "Wrong file type submitted!" });
}
// Getting extension of any image
const imageExtension = filename.split(".")[
filename.split(".").length - 1
];
// Setting filename
imageFileName = `${Math.round(
Math.random() * 1000000000
)}.${imageExtension}`;
// Creating path
const filepath = path.join(os.tmpdir(), imageFileName);
imageToBeUploaded = { filepath, mimetype };
file.pipe(fs.createWriteStream(filepath));
});
busboy.on("finish", () => {
admin
.storage()
.bucket()
.upload(imageToBeUploaded.filepath, {
destination: `${folder}/${imageFileName}`,
resumable: false,
metadata: {
metadata: {
contentType: imageToBeUploaded.mimetype
}
}
})
.then(() => {
const imageUrl = `https://firebasestorage.googleapis.com/v0/b/${config.storageBucket}/o${folder}%2F${imageFileName}?alt=media`;
if (url === `/users/${req.user.alias}`) {
return db.doc(`${url}`).update({ imageUrl });
} else {
return res.json({ imageUrl });
}
})
.then(() => {
return res.json({
message: "Image uploaded successfully!"
});
})
.catch(err => {
console.log(err);
return res.status(500).json({ error: err.code });
});
});
busboy.end(req.rawBody);
};
任何建议如何继续?
您的代码几乎完成了,您要做的就是创建一个promise数组,并等待所有这些都解决。
let imageFileName = {}
let imagesToUpload = []
let imageToAdd = {}
//This triggers for each file type that comes in the form data
busboy.on("file", (fieldname, file, filename, encoding, mimetype) => {
if (mimetype !== "image/jpeg" && mimetype !== "image/png") {
return res
.status(400)
.json({ error: "Wrong file type submitted!" });
}
// Getting extension of any image
const imageExtension = filename.split(".")[
filename.split(".").length - 1
];
// Setting filename
imageFileName = `${Math.round(
Math.random() * 1000000000
)}.${imageExtension}`;
// Creating path
const filepath = path.join(os.tmpdir(), imageFileName);
imageToAdd = {
imageFileName
filepath,
mimetype };
file.pipe(fs.createWriteStream(filepath));
//Add the image to the array
imagesToUpload.push(imageToAdd);
});
busboy.on("finish", () => {
let promises = []
let imageUrls = []
imagesToUpload.forEach(imageToBeUploaded => {
imageUrls.push(`https://firebasestorage.googleapis.com/v0/b/${config.storageBucket}/o${folder}%2F${imageFileName}?alt=media`)
promises.push(admin
.storage()
.bucket()
.upload(imageToBeUploaded.filepath, {
destination: `${folder}/${imageFileName}`,
resumable: false,
metadata: {
metadata: {
contentType: imageToBeUploaded.mimetype
}
}
}))
})
try{
await Promises.all(resolve)
res.status(200).json({msg: 'Successfully uploaded all images', imageUrls})
}catch(err){ res.status(500).json(err) }
});
busboy.end(req.rawBody);
有了该功能,您就可以全部上传它们,只需将所有的Promise放入数组中并使用Promise.all
方法来等待它们解决即可。我使用async / await做到了,因为这就是我一直这样做的方式,但是我想您在使用回调进行此操作时将没有问题。
而且代码很凌乱,但这主要是因为我不知道如何使用此文本编辑器,希望您仍然能够理解它👀