我的回声“

Question

echo "<tr class ='a'>
<td>".$data->id."</td>
<td>".$data->nis."</td>
<td>".$data->nama."</td>
<td>".$data->jenis_kelamin."</td>
<td>".$data->telp."</td>
<td>".$data->alamat."</td>
<td><a class="btn btn-warning" href="'.base_url("siswa/ubah/".$data->id).'">Ubah</a></td>
<td><a class="btn btn-danger" href="'.base_url("siswa/hapus/".$data->id).'">Hapus</a></td>
</tr>";

我在编码中使用bootstrap时出现错误，如何防止错误？

Answer 1

试试吧

<?php
    echo "<tr class ='a'>
    <td>".$data->id."</td>
    <td>".$data->nis."</td>
    <td>".$data->nama."</td>
    <td>".$data->jenis_kelamin."</td>
    <td>".$data->telp."</td>
    <td>".$data->alamat."</td>
    <td><a class=\"btn btn-warning\" href=".base_url("siswa/ubah/".$data->id).">Ubah</a></td>
    <td><a class=\"btn btn-warning\" href=".base_url("siswa/hapus/".$data->id).">Hapus</a></td>    
    </tr>";
    ?>

Answer 2

试试这个方法。希望它会对你有所帮助

<td><?php echo $data->id; ?></td>

<td><?php echo $data->ins; ?></td>

<td><?php echo $data->name; ?></td>

<td><?php echo $data->jenis_kelamin; ?></td>

<td><?php echo $data->telp; ?></td>

<td><?php echo $data->alamat; ?></td>

<td><a class=\"btn btn-warning\" href="<php echo base_url("siswa/ubah/".$data->id)?>">Ubah</a></td>

<td><a class=\"btn btn-warning\" href="<?php echo base_url("siswa/hapus/".$data->id)?>">Hapus</a></td>