discord.py 斜线权限

Question

如何为discord.pylash-commands命令添加权限？斜杠命令中没有@has_permissions()。

@slash.slash(
    name="kick",
    description="Kicks member from the server",
    options=[manage_commands.create_option(
        name = "member",
        description = "Who do you want to kick?",
        option_type = 3,
        required = True
        ),
        manage_commands.create_option(
        name = "reason",
        description = "What is the reason?",
        option_type = 3,
        required = False
        )])
async def _kick(ctx, member: discord.Member, reason='Unspecified'):
    await ctx.send(0)
    await member.kick(reason=reason)
    e=discord.Embed(title="🔨 Banhammer has spoken", color=0xfa2d4c)
    e.add_field(name='Kick', value=f' :white_check_mark: Kicked {member} for `{reason}`', inline=False)
    await ctx.channel.send(embed=e)```

Answer 1

由于目前没有 (discord-py-slash-command)[https://pypi.org/project/discord-py-slash-command/] 的权限检查，您可以在代码中检查成员是否有某个权限，如下图

@slash.slash(name="cool_command")
async def cool_command(ctx, option):
    if not ctx.author.guild_permissions.manage_messages: # replace this with your desired permission
        return # tell them they dont have permissions or raise an exception
    ... # do your stuff here

Answer 2

Discord.py 尚不支持斜杠命令。 同时，您可以使用 discord-py-slash-command 来使用斜线命令。 希望这有帮助

Answer 3

好吧，我尝试使用

@commands.has_permissions()

，就我而言它仍然有效。您可以使用测试命令尝试一下，它应该响应：

互动失败

如果您不是这样，请告诉我

Answer 4

现在，当您生成 ouath2 令牌来邀请机器人时，有斜杠命令权限，而不是仅添加“bot”，添加“bot”和“applications.commands”

Discord.py 没有实际支持斜杠命令，只有 api，但这里有一个不同的下载：

https://pypi.org/project/discord-py-slash-command/

Answer 5

下

@slash.slash(name=“Kick”, description=“Kicks the member”)

添加：

@commands.has_permissions(kick_members=True)

就这样吧。应该有效

Answer 6

使用 dpy 2.0 执行斜杠命令

您需要在开发人员门户中注册命令 和 使其具有应用程序命令范围才能正常工作。

from discord.ext import commands
from discord import app_commands

bot = commands.Bot(prefix="...")

@bot.event
async def on_ready():
    bot.tree.sync(guild=discord.Object(id=...)) # id is guild id(s) 
    # Global bot.tree.sync()
    ...

@bot.tree.command(name="num")
    async def num(self, inter, number : app_commands.Range[int,10,12]):
        await interaction.response.send_message(f'Your value is {value}', ephemeral=True)

类方法

from discord.ext import commands

class Bot:
    def __init__(self, ...):
        ...

    async def on_ready(self): # Not recommended
        await self.tree.sync(guild=discord.Object(id=...))
        ...

齿轮：

from discord import app_commands
from discord.ext import commands

class Cog(commands.Cog):
    def __init__(self, bot):
        self.bot = bot

    @app_commands.command(name="num")
    async def num(self, inter, number : app_commands.Range[int,10,12]):
        await interaction.response.send_message(f'Your value is {value}', ephemeral=True)

async def setup(bot):
    bot.add_cog(Cog(bot))

https://discordpy.readthedocs.io/en/latest/interactions/api.html?highlight=app_commands#discord.app_commands.Range

Answer 7

使用@discord.app_commands.checks.has_permissions（这里输入你的权限），但是需要导入 from discord import app_commands

@slash.slash(
    name="kick",
    description="Kicks member from the server",
    options=[manage_commands.create_option(
        name = "member",
        description = "Who do you want to kick?",
        option_type = 3,
        required = True
        ),
        manage_commands.create_option(
        name = "reason",
        description = "What is the reason?",
        option_type = 3,
        required = False
        )])
@discord.app_commands.checks.has_permissions(manage_roles=True)
async def _kick(ctx, member: discord.Member, reason='Unspecified'):
    await ctx.send(0)
    await member.kick(reason=reason)
    e=discord.Embed(title="🔨 Banhammer has spoken", color=0xfa2d4c)
    e.add_field(name='Kick', value=f' :white_check_mark: Kicked {member} for `{reason}`', inline=False)
    await ctx.channel.send(embed=e)```