从 wiki 标记中删除方括号

Question

我正在寻找从维基文本中删除一些标记的方法。

示例：

Mexico, officially the United Mexican States, is a [wiki=1c1ff8db21cf79377f9930e6e6ff8247]country[/wiki] in the southern portion of [wiki=5ffec2d87ab548202f8b549af380913a]North America[/wiki].

返回的文本应该是：

Mexico, officially the United Mexican States, is a country in the southern portion of North America.

我们尝试过的：

preg_replace('/(\[.*?.\])/', '', $txt)

谢谢。

Answer 1

修改模式以替换打开标签和关闭标签之间的文本。

$markup = 'Mexico, officially the United Mexican States, is a [wiki=1c1ff8db21cf79377f9930e6e6ff8247]country[/wiki] in the southern portion of [wiki=5ffec2d87ab548202f8b549af380913a]North America[/wiki].';
$plain = preg_replace('/\[.*?\](.*?)\[\/.*?\]/', '$1', $markup);
echo $plain;

输出

Mexico, officially the United Mexican States, is a country in the southern portion of North America.

Answer 2

如果你想匹配wiki：你可以使用：

\[wiki=[^][]*](.+?)\[/wiki]

解释

• \[wiki=

  匹配

  [wiki=
• [^][]*

   可选择重复匹配除 

  [

   或 

  ] 之外的任何字符
• ]

   匹配右方括号

• (.+?)

   捕获第1组，尽可能匹配1+个字符

• \[/wiki]

  匹配

  [/wiki]

在替换使用组 1 中，如

$1

正则表达式演示

示例

$re = '`\[wiki=[^][]*](.+?)\[/wiki]`m';
$str = 'Mexico, officially the United Mexican States, is a [wiki=1c1ff8db21cf79377f9930e6e6ff8247]country[/wiki] in the southern portion of [wiki=5ffec2d87ab548202f8b549af380913a]North America[/wiki].
';

$result = preg_replace($re, '$1', $str);

echo $result;

输出

Mexico, officially the United Mexican States, is a country in the southern portion of North America.