我想要改组3D矩阵的行,但它不能在矩阵中工作,这里是一些示例代码
def shuffle(data,data_size):
for step in range(int(1*data_size)):
selected = int(np.random.uniform(0,data_size))
target = int(np.random.uniform(0,data_size))
print(data)
if selected!=target:
data[selected], data[target] = data[target], data[selected]
print(selected," and ",target, " are changed")
return data
data = [[[1,2,3,4],[1,2,3,5],[1,2,3,6]],
[[2,2,3,4],[2,2,3,5],[2,2,3,6]],
[[3,2,3,4],[3,2,3,5],[3,2,3,6]] ]
data = np.array(data)
data = shuffle(data,3)
在这段代码中,我想将数据从某些行列表改为另一行列表
但它的结果不能交换,而是覆盖
这是结果
[[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]
[[3 2 3 4]
[3 2 3 5]
[3 2 3 6]]]
2 and 1 are changed
[[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]]
1 and 0 are changed
[[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]]
0 and 2 are changed
[[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]
[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]]
2 and 1 are changed
我怎么能在矩阵中交换列表?
谢谢
import numpy as np
def shuffle(data,data_size):
for step in range(int(1*data_size)):
selected = int(np.random.uniform(0,data_size))
target = int(np.random.uniform(0,data_size))
print(data)
if selected!=target:
data[[selected, target]] = data[[target, selected]]
print(selected," and ",target, " are changed")
return data
data = [[[1,2,3,4],[1,2,3,5],[1,2,3,6]],
[[2,2,3,4],[2,2,3,5],[2,2,3,6]],
[[3,2,3,4],[3,2,3,5],[3,2,3,6]] ]
data = np.array(data)
data = shuffle(data,3)
如果你想沿第一轴移动,只需使用np.random.shuffle
:
data = np.array([
[[1,2,3,4],[1,2,3,5],[1,2,3,6]],
[[2,2,3,4],[2,2,3,5],[2,2,3,6]],
[[3,2,3,4],[3,2,3,5],[3,2,3,6]]
])
np.random.shuffle(data)
print(data)
输出:
[[[3 2 3 4]
[3 2 3 5]
[3 2 3 6]]
[[1 2 3 4]
[1 2 3 5]
[1 2 3 6]]
[[2 2 3 4]
[2 2 3 5]
[2 2 3 6]]]
如果你想在data
中沿着任何其他轴移动,你可以随机播放np.swapaxes
返回的数组视图。例如,要对内部2D矩阵的行进行随机排列,请执行以下操作:
swap = np.swapaxes(data, 1, 0)
np.random.shuffle(swap)
print(data)
输出:
[[[1 2 3 6]
[1 2 3 4]
[1 2 3 5]]
[[2 2 3 6]
[2 2 3 4]
[2 2 3 5]]
[[3 2 3 6]
[3 2 3 4]
[3 2 3 5]]]