我正在修复一个错误，该错误仅在客户端使用 HTTP/1.0 时才会显现出来（并且是秘密的，Internet Explorer 在防火墙后面代理）。
详细信息在这里：https://issues.apache.org/jira/browse/TAP5-1880
无论如何，正确的解决方案是在请求是 HTTP/1.0 时关闭一项功能（GZip 内容压缩）。然而，在搜索了 Servlet API 文档，甚至 Jetty 源代码之后，我找不到任何暴露此信息的地方。
那么，有没有办法确定这一点呢？我正在使用
Servlet API 2.5提前致谢！
request.getProtocol() will return "HTTP/1.0" or "HTTP/1.1"
这里是例子，在你本地的tomcat中执行
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.*;
public class ShowRequestHeaders extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
String title = "Servlet Example: Showing Request Headers";
out.println(ServletUtilities.headWithTitle(title) +
"<BODY BGCOLOR=\"#FDF5E6\">\n" +
"<H1 ALIGN=CENTER>" + title + "</H1>\n" +
"<B>Request Method: </B>" +
request.getMethod() + "<BR>\n" +
"<B>Request URI: </B>" +
request.getRequestURI() + "<BR>\n" +
"<B>Request Protocol: </B>" +
request.getProtocol() + "<BR><BR>\n" +
"<TABLE BORDER=1 ALIGN=CENTER>\n" +
"<TR BGCOLOR=\"#FFAD00\">\n" +
"<TH>Header Name<TH>Header Value");
Enumeration headerNames = request.getHeaderNames();
while(headerNames.hasMoreElements()) {
String headerName = (String)headerNames.nextElement();
out.println("<TR><TD>" + headerName);
out.println(" <TD>" + request.getHeader(headerName));
}
out.println("</TABLE>\n</BODY></HTML>");
}
public void doPost(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
doGet(request, response);
}
}