check50 命令返回我的 print_winner 函数的错误

Question

print_winner 函数必须找到得票最高的候选人并打印其名字。如果有两名候选人拥有相同的票数，该函数必须打印 2 个名字。

这里有错误

:( print_winner identifies Alice as winner of election
    print_winner function did not print winner of election
:( print_winner identifies Bob as winner of election
    print_winner function did not print winner of election
:( print_winner identifies Charlie as winner of election
    print_winner function did not print winner of election
:( print_winner prints multiple winners in case of tie
    print_winner function did not print both winners of election
:( print_winner prints all names when all candidates are tied
    print_winner function did not print all three winners of election

这是我的功能代码

void print_winner(void)
{
    int maxx;
    maxx = candidates[0].votes;
    for (int i = 1; i < candidate_count; i++)
    {
        if(maxx < candidates[i].votes)
        {
            maxx = candidates[i].votes;
        }
    }
    for (int j = 0; j < candidate_count; j++)
    {
        if (candidates[j].votes == maxx)
        {
            printf("%s \n", candidates[j].name);
        }
    }
}

Answer 1

来自规格

该函数应打印出在选举中获得最多选票的候选人的姓名，然后打印换行符。

此

printf("%s \n", candidates[j].name);

打印候选人的姓名，一个空格，然后是换行符。这看起来似乎是一个微不足道的差异，实际上人眼无法察觉，但 check50 没有找到与预期输出完全匹配的结果。