任何人都知道jquery或javascript中是否有与原型toPaddedString方法匹配的等效方法?
在jQuery中没有与之匹配的东西,但是在这里,我鞭打了您使用the Prototype method的纯Javascript版本:
function toPaddedString(number, length, radix) {
var string = number.toString(radix || 10),
slength = string.length;
for (var i=0; i<(length - slength); i++) string = '0' + string;
return string;
}
toPaddedString(13, 4); // "0013"
String.prototype.padLeft=function(n, s){
var t= this, L= s.length;
while(t.length+L<= n) t= s+t;
if(t.length<n) t= s.substring(0, n-t)+t;
return t;
}
String.prototype.padRight=function(n, s){
var t= this, L= s.length;
while(t.length+L<= n) t+=s;
if(t.length< n) t+= s.substring(0, n-t);
return t;
}