我有这三个表,我想获得链接到表1的表3的价格字段的总和,将表2链接到表1和3的表2:
表1-技术
+--------------+------------+
| id_tecnic | name |
+--------------+------------+
| 1 | Michael |
| 2 | Billy |
| 3 | Joe |
+--------------+------------+
表2-链接
+--------------+------------+------------+
| id_linked | id_tecnic | id_mer |
+--------------+------------+------------+
| 1 | 1 | 4 |
| 2 | 3 | 1 |
| 3 | 3 | 2 |
+--------------+------------+------------+
表3-Mer
+--------------+------------+
| id_mer | price |
+--------------+------------+
| 1 | 30 |
| 2 | 70 |
| 3 | 50 |
| 4 | 10 |
+--------------+------------+
结果
+--------------+------------+-------------+
| id_tecnic | name | total_price |
+--------------+------------+-------------+
| 1 | Michael | 10 |
| 2 | Billy | 0 |
| 3 | Joe | 90 |
+--------------+------------+-------------+
我已经尝试过:
SELECT te.id_tecnic,
SUM(m.price)
FROM tecnic te
LEFT JOIN linked l ON te.id_tecnic = l.id_tecnic
LEFT JOIN mer m ON l.id_mer = m.id_mer
GROUP BY te.id_tecnic
[Billy在Table 2 - Linked
中没有记录,因此为了在结果集中包含Billy,您必须从表Table 3 - Mer
开始,例如:
SELECT te.id_tecnic, te.name, SUM(m.price)
FROM mer m
LEFT jOIN linked l ON l.id_mer = m.id_mer
LEFT JOIN te ON te.id_tecnic = l.id_tecnic
GROUP BY te.id_tecnic;