什么是填充一个临时表的日期，包括2个日期参数之间的最简单的方法。我只需要一个月中日期的第一天。
因此，举例来说，如果@StartDate = '2011-01-01' 和@EndDate = '2011-08-01'
然后我想这回在表
2011-01-01
2011-02-01
2011-03-01
2011-04-01
2011-05-01
2011-06-01
2011-07-01
2011-08-01
这个工程即使@StartDate并非当月的第一天。我假设，如果不是这个月的开始，你要开始与第一下个月。否则删除+1：
;WITH cte AS (
SELECT CASE WHEN DATEPART(Day,@StartDate) = 1 THEN @StartDate
ELSE DATEADD(Month,DATEDIFF(Month,0,@StartDate)+1,0) END AS myDate
UNION ALL
SELECT DATEADD(Month,1,myDate)
FROM cte
WHERE DATEADD(Month,1,myDate) <= @EndDate
)
SELECT myDate
FROM cte
OPTION (MAXRECURSION 0)
declare @StartDate date = '2014-01-01';
declare @EndDate date = '2014-05-05';
;WITH cte AS (
SELECT @StartDate AS myDate
UNION ALL
SELECT DATEADD(day,1,myDate) as myDate
FROM cte
WHERE DATEADD(day,1,myDate) <= @EndDate
)
SELECT myDate
FROM cte
OPTION (MAXRECURSION 0)
declare @StartDate datetime
declare @EndDate datetime
select @StartDate = '2011-01-01' , @EndDate = '2011-08-01'
select @StartDate= @StartDate-(DATEPART(DD,@StartDate)-1)
declare @temp table
(
TheDate datetime
)
while (@StartDate<=@EndDate)
begin
insert into @temp
values (@StartDate )
select @StartDate=DATEADD(MM,1,@StartDate)
end
select * from @temp
通过返回到起始日期的当月的第一天始工作，即使@StartDate不是该月的第一天
这是在2008年SQL R2测试
Declare @StartDate datetime = '2015-03-01'
Declare @EndDate datetime = '2015-03-31'
declare @temp Table
(
DayDate datetime
);
WHILE @StartDate <= @EndDate
begin
INSERT INTO @temp (DayDate) VALUES (@StartDate);
SET @StartDate = Dateadd(Day,1, @StartDate);
end ;
select * from @temp
结果：
DayDate
-----------------------
2015-03-01 00:00:00.000
2015-03-02 00:00:00.000
2015-03-03 00:00:00.000
2015-03-04 00:00:00.000
...
解：
DECLARE @StartDate DATETIME
,@EndDate DATETIME;
SELECT @StartDate = '20110105'
,@EndDate = '20110815';
SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, DATEADD(MONTH, v.number, @StartDate)), 0) AS FirstDay
--or Andriy M suggestion:
--SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, @StartDate) + v.number, 0) AS FirstDay
INTO #Results
FROM master.dbo.spt_values v
WHERE v.type = 'P'
AND DATEDIFF(MONTH, @StartDate, @EndDate) >= v.number;
SELECT *
FROM #Results;
DROP TABLE #Results;
结果：
FirstDay
-----------------------
2011-01-01 00:00:00.000
2011-02-01 00:00:00.000
2011-03-01 00:00:00.000
2011-04-01 00:00:00.000
2011-05-01 00:00:00.000
2011-06-01 00:00:00.000
2011-07-01 00:00:00.000
2011-08-01 00:00:00.000
有趣的是，这是更快地从列举的数据按照this article创建。
DECLARE @StartDate DATE = '10001201';
DECLARE @EndDate DATE = '20000101';
DECLARE @dim TABLE ([date] DATE)
INSERT @dim([date])
SELECT d
FROM
(
SELECT
d = DATEADD(DAY, rn - 1, @StartDate)
FROM
(
SELECT TOP (DATEDIFF(DAY, @StartDate, @EndDate))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM
sys.all_objects AS s1
CROSS JOIN
sys.all_objects AS s2
ORDER BY
s1.[object_id]
) AS x
) AS y;
在我的机器，它的周围有大日期范围快60％。递归方法可以填充2000年有价值的数据在3秒左右，虽然，看起来要好很多，所以我真的不建议使用这种方法只是为了增加天。
修正空日期：
IF OBJECT_ID('tempdb..#dim') IS NOT NULL
DROP TABLE #dim
CREATE TABLE #dim ([date] DATE)
if not @Begin_Date is null and not @End_Date is null
begin
INSERT #dim([date])
SELECT d
FROM(
SELECT
d = DATEADD(DAY, rn - 1, @Begin_Date)
FROM
(
SELECT TOP (DATEDIFF(DAY, @Begin_Date, @End_Date))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM
sys.all_objects AS s1
CROSS JOIN
sys.all_objects AS s2
ORDER BY
s1.[object_id]
) AS x
) AS y;
end
CREATE TABLE #t (d DATE)
INSERT INTO #t SELECT GETDATE()
GO
INSERT #t SELECT DATEADD(DAY, -1, MIN(d)) FROM #t
GO 10