如何使用java类和lombok的构建器创建以下json?
我使用了一些json to pojo工具并创建了2个类:Entry.java
和Testplan.java
,添加了一个方法将String
转换为json并设法获得一个json对象:{"suite_id":99,"name":"Some random name"}
我不明白如何创建一个看起来像这样的:
{
"name": "System test",
"entries": [
{
"suite_id": 1,
"name": "Custom run name"
},
{
"suite_id": 1,
"include_all": false,
"case_ids": [
1,
2,
3,
5
]
}
]
}
test plan.Java
@Data
@Builder
public class Testplan {
@JsonProperty("name")
public String name;
@JsonProperty("entries")
public List<Entry> entries = null;
}
entry.Java
@Data
@Builder
@NoArgsConstructor
@AllArgsConstructor
@JsonInclude(JsonInclude.Include.NON_NULL)
public class Entry {
@JsonProperty("suite_id")
public Integer suiteId;
@JsonProperty("name")
public String name;
@JsonProperty("include_all")
public Boolean includeAll;
@JsonProperty("case_ids")
public List<Integer> caseIds = null;
}
我使用这个将String转换为json:
public <U> String toJson(U request) throws JsonProcessingException {
ObjectMapper mapper = new ObjectMapper()
.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
return mapper.writeValueAsString(request);
}
这是我开始创建对象并陷入困境的方式:
public static Entry getRequestTemplate() {
Entry entry = new Entry();
entry.setName("Here's some name");
entry.setSuiteId(16);
return entry;
}
为了看看发生了什么,我添加了这个:
@Test
public void showJson() throws JsonProcessingException {
String json = toJson(getRequestTemplate());
System.out.println(json);
}
我希望必须结合这两个类并创建一个case_ids
列表,但不能包围我的头。
这有效:
Testplan
的新方法: public Testplan kek2() {
Testplan testplan = Testplan.builder()
.name("System test")
.entries(Lists.newArrayList(Entry.builder()
.name("Custom run name")
.suiteId(1)
.includeAll(false)
.caseIds(new ArrayList<>(Arrays.asList(1, 2, 3, 4, 5)))
.build()))
.build();
System.out.println(testplan);
return testplan;
}
protected <U> String toJson(U request) throws JsonProcessingException {
ObjectMapper mapper = new ObjectMapper();
return mapper.writeValueAsString(request);
}