Php，如果是/否

Question

我试图将功能添加到脚本中，要求用户输入我已添加的代码。但有一个问题我希望无法何时询问用户代码以及何时询问。所以我需要一个PHP，如果否则，它的SQL因此，当我无法向用户询问代码时，它将询问代码，而当我禁用它时，它将不会询问代码以下是我尝试过的一个

if ((['yes'])) {
  // Yes

<div id="cot_div" align="center">
    <p>Please enter your <strong id="code_up">COT</strong> code to continue</p>



    <form id="form3" name="form3" method="POST" action="inter_suc.php">  
   <table border="0" id="trans" align="center" >
  <tr>
    <td align="center" style="padding:0px"><span id="sprytextfield1">
      <input name="cot" type="text" id="cot" size="10" />
      <span class="textfieldRequiredMsg"></span></span>

      <span id="sprytextfield2">
      <input name="tax" type="text" id="tax" size="10" />
      <span class="textfieldRequiredMsg"></span></span>
      <span id="sprytextfield3">
      <input name="imf" type="text" id="imf" size="10"  />
      <span class="textfieldRequiredMsg"></span></span><br />  <span id="error">
      wrong COT Code</span>
      </td>
    </tr>
  <tr>
    <td align="center" style="padding:0px"><input type="button" name="go" id="go" value="Go" />
      <input type="button" name="go2" id="go2" value="GO" />
      <input type="button" name="go3" id="go3" value="GO" />

    </td>
  </tr>

} else {
  // No

<div id="cot_div" align="center">
    <p>Please enter your <strong id="code_up">COT</strong> code to continue</p>



    <form id="form3" name="form3" method="POST" action="inter_suc.php">  
   <table border="0" id="trans" align="center" >
  <tr>
    <td align="center" style="padding:0px"><span id="sprytextfield1">
        <input name="cot" type="hidden" id="cot" value="<?php echo $_POST['cot'];?>" />
      <span class="textfieldRequiredMsg"></span></span>

      <span id="sprytextfield2">
      <input name="tax" type="hidden" id="tax" value="<?php echo $_POST['tax'];?>" />
      <span class="textfieldRequiredMsg"></span></span>
      <span id="sprytextfield3">
       <input name="imf" type="hidden" id="imf" value="<?php echo $_POST['imf'];?>" />
      <span class="textfieldRequiredMsg"></span></span><br />  <span id="error">
      wrong COT Code</span>
      </td>
    </tr>
  <tr>
    <td align="center" style="padding:0px"><input type="button" name="go" id="go" value="Go" />
      <input type="button" name="go2" id="go2" value="GO" />
      <input type="button" name="go3" id="go3" value="GO" />

    </td>
  </tr>

}

Answer 1

如果我理解您的回答是正确的，那么如果您在php中给定的变量为'是'，则您想显示特定的HTML部分。否则，您想显示HTML的其他部分。

比您可以使用以下语法：

<?php if ($val = 'YES'): ?>
  <!-- Yes part -->
<?php else: ?>
  <!-- No part -->
<?php endif; ?>

Answer 2

您的意思是这样的？

.error {
  display: none
}

<?php
  $yes = $_GET["yes"] == "yes"; ?>
<div id="cot_div" align="center">
  <p>Please enter your <strong id="code_up">COT</strong> code to continue</p>
  <form id="form3" name="form3" method="POST" action="inter_suc.php">
    <table border="0" id="trans" align="center">
      <tr>
        <td align="center" style="padding:0px">
          <span id="sprytextfield1"><input name="cot" type="<?php echo $yes ? "text" : "hidden"; ?>" id="cot" size="10" /></span>
          <span class="textfieldRequiredMsg"></span>
          <span id="sprytextfield2"><input name="tax" type="<?php echo $yes ? "text" : "hidden"; ?>" id="tax" size="10" /></span>
          <span class="textfieldRequiredMsg"></span>
          <span id="sprytextfield3"><input name="imf" type="<?php echo $yes ? "text" : "hidden"; ?>" id="imf" size="10"  /></span>    
          <span class="textfieldRequiredMsg"></span><br /> 
          <span id="error">wrong COT Code</span>
       </td>
    </tr>
    <tr>
      <td align="center" style="padding:0px">
        <input type="button" name="go" id="go" value="Go" />
        <input type="button" name="go2" id="go2" value="GO" />
        <input type="button" name="go3" id="go3" value="GO" />
      </td>
    </tr>
  </table>
  </div>