GridSearchCV scikit-learn.TypeError LogisticRegression...没有实现'get_params'方法。TypeError LogisticRegression...没有实现'get_params'方法。

问题描述 投票:0回答:1

我想使用sklearn的GridSearchCV来优化逻辑回归估计器的超参数(参见 https:/towardsdatascience.comhyperparameter-tuning-c5619e7e6624。),基于以下代码。

X_train, X_test, y_train, y_test,indices_train,indices_test = train_test_split(features_all2, df_all['labels'], df_all.index, test_size=0.25, random_state=1)

penalty = ['l1', 'l2']
C = [0.0001, 0.001, 0.01, 0.1, 1, 10, 100, 1000]
class_weight = ['balanced']
solver = ['liblinear', 'saga']

param_grid = dict(penalty=penalty,
                  C=C,
                  class_weight=class_weight,
                  solver=solver)

grid = GridSearchCV(estimator=LogisticRegression,
                    param_grid=param_grid,
                    scoring='roc_auc',
                    verbose=1,
                    n_jobs=-1)
grid_result = grid.fit(X_train, y_train)

print('Best Score: ', grid_result.best_score_)
print('Best Params: ', grid_result.best_params_)

它工作得很好,直到 grid_result = grid.fit(X_train, y_train) 我得到的错误 TypeError.无法克隆对象'' (type ):似乎不是scikit-learn估计器,因为它没有实现'get_params'方法。无法克隆对象''(type ):它似乎不是一个scikit-learn估计器,因为它没有实现'get_params'方法。

虽然当做 hasattr(LogisticRegression, 'get_params') 我得到 .

我被卡在这里。有谁可能有一个想法,如何处理这个问题?非常感谢!我想用sklearn的GridSearchCV优化逻辑回归估计器的超参数(见ttps)。

python typeerror clone logistic-regression gridsearchcv
1个回答
0
投票

你需要通过 estimator= LogisticRegression() 而不是 estimator= LogisticRegression

例如:

from sklearn.model_selection import GridSearchCV
from sklearn.linear_model import LogisticRegression
grid={"C":np.logspace(-3,3,7), "penalty":["l1","l2"]}# l1 lasso l2 ridge
logreg=LogisticRegression()
logreg_cv=GridSearchCV(logreg,grid,cv=10)
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