缺少Python位置参数

Question

我已经编写了要在清除的文本上执行的代码。我已经写了代码。但是它显示出各种错误。

代码如下：

class a:
    def __init__(self):
        self.text = " "
    def __str__(self):
        return self.text
    def fun1(self,b):
         self.d1 = dict()
         ch = '@#$%^&*)('
         with open(b,'r') as g:
             g = g.read()
             if any(m in ch for m in g):
                 print("hi")
             else:
                 w = g.split()
             for i in w:
                 if in self.d1:
                     self.d1[i] += 1
                 else:
                     self.d1[i] = 1
         return self.d1
     def fun2(self):
         b = self.fun1()
         w1 = dict()
         c = len(b.d1)
         for w in b.d1:
             w1[w] = b[d1]/c
         return w1

f = a()
f.fun2(b)

引发错误fun1缺少1个必需的位置参数：b

Answer 1

功能fun1需要参数b，但您不传递它。如果不需要参数b，请从fun1的参数中删除它，否则在调用b时传递参数fun1的值。

---

几乎很难理解您想做什么，但是我认为您先对单词进行计数，然后针对句子词汇的长度对其进行规范化。这绝对不是最好的方法。但是现在至少它可以正常工作并且有意义：

class a:
    def __init__(self):
        self.text = " "

    def __str__(self):
        return self.text

    def fun1(self, filepath):
        d1 = {}
        with open(filepath,'r') as g: 
            g = g.read()
            w = g.split()

        #example input for test
        #g = "I love pizza and I love chips" # fake input
        #w = g.split()
            for i in w:
                d1[i] = d1[i] + 1 if i in d1 else 1

        return d1

    def fun2(self):
         d1 = self.fun1(filepath='corpus.txt')
         w1 = {}
         c = len(d1) # Or did you mean by the total number of words? Which you can calculate like this: sum(d1.values()))

         for w in d1:
             w1[w] = d1[w]/c
         return w1

f = a()
f.fun2()
以及输入示例（有注释）给出：

# {'I': 0.4, 'love': 0.4, 'pizza': 0.2, 'and': 0.2, 'chips': 0.2}