MySQL错误:#1142 - TRIGGER命令被拒绝

问题描述 投票:0回答:3

我需要我的MySQL数据库在特定的coloumn中得到一些值的总和。为此,我使用了触发器语句,但MySQL给了我一个错误:

MySQL错误:#1142 - TRIGGER命令拒绝用户'XXXXXX'表wp wpdatatables 8

触发器如下:

CREATE TRIGGER SumPliche AFTER INSERT ON wp_wpdatatable_8 FOR EACH ROW UPDATE wp_wpdatatable_8 SET sommapliche = tricipite + addome + soprailiaca + sottoscapolare + ascellare + pettorale + coscia

我怎样才能做到这一点?谢谢

mysql triggers grant
3个回答
1
投票

看来这里的问题是你的用户对wp_wpdatatable_8数据库的权限。

要授予特定用户和数据库的触发器权限,可以使用以下命令:

mysql> GRANT TRIGGER ON <DATABASE>.* TO <USER>@'<DATABASE HOST>';

哪里

  • <DATABASE>指的是包含wp_wpdatatable_8表的数据库。
  • <USER>尝试发出CREATE TRIGGER命令的用户名。
  • 用户访问数据库的<DATABASE HOST>数据库主机。如果您在本地运行它,您可以使用localhost

刷新权限后,创建触发器应该正常工作。

有关更多信息,请查看MySQL.documentation上的GRANT语法


1
投票

您在使用的数据库上缺少TRIGGER权限。

我做测试时遇到了这个错误。创建测试用户:

mysql> create user 'bill'@'localhost';
mysql> grant all privileges on test2.* to 'bill'@'localhost';
mysql> revoke trigger on test2.* from 'bill'@'localhost';
mysql> show grants for 'bill'@'localhost';
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Grants for bill@localhost                                                                                                                                                                                                    |
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| GRANT USAGE ON *.* TO 'bill'@'localhost' IDENTIFIED BY PASSWORD '*29A1BB43D3B9EB42028B4566E4836353285B9395'                                                                                                                  |
| GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES, EXECUTE, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE, EVENT ON `test2`.* TO 'bill'@'localhost' |
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

现在尝试以此用户创建触发器:

~ mysql -ubill -p
mysql> use test2
mysql> create table t ( i int);
mysql> create trigger tt before insert on t for each row set new.i = 42;
ERROR 1142 (42000): TRIGGER command denied to user 'bill'@'localhost' for table 't'

我也认为你的触发器可能不会做你认为它做的事情,所以你没有创建它也是如此。

CREATE TRIGGER SumPliche AFTER INSERT ON wp_wpdatatable_8 
FOR EACH ROW 
  UPDATE wp_wpdatatable_8 
  SET sommapliche = tricipite + addome + soprailiaca + sottoscapolare + ascellare + pettorale + coscia

如果我在我的测试数据库中创建此触发器(作为具有TRIGGER权限的其他用户),然后尝试插入一行:

mysql> insert into wp_wpdatatable_8 values (1, 1, 1, 1, 1, 1, 1, 1);
ERROR 1442 (HY000): Can't update table 'wp_wpdatatable_8' in 
stored function/trigger because it is already used by statement which invoked 
this stored function/trigger.

您可能只想在插入的行中设置值。如果是这样,您将使用NEW.*语法引用当前行:

CREATE TRIGGER SumPliche BEFORE INSERT ON wp_wpdatatable_8 
FOR EACH ROW 
  SET NEW.sommapliche = NEW.tricipite + NEW.addome + NEW.soprailiaca 
    + NEW.sottoscapolare + NEW.ascellare + NEW.pettorale + NEW.coscia;

如果要在插入行之前更改行中的值,也必须使用BEFORE INSERT。如果你使用AFTER INSERT,那就太晚了。

它现在有效:

mysql> insert into wp_wpdatatable_8 values (1, 1, 1, 1, 1, 1, 1, 1);
Query OK, 1 row affected (0.02 sec)

mysql> select * from wp_wpdatatable_8;
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+
| sommapliche | tricipite | addome | soprailiaca | sottoscapolare | ascellare | pettorale | coscia |
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+
|           7 |         1 |      1 |           1 |              1 |         1 |         1 |      1 |
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+

0
投票

如果我使用

GRANT TRIGGER ON wordpress-5478r34b.* TO '_sso_67c5vh1'@'10.3.157.568'

1064 - Syntax Error in SQL query near to '-5478r34b.* TO '_sso_67c5vh1'@'10.3.157.568'' linea 1

要么

'wordpress-3236c57b'上的GRANT TRIGGER。* TO'_sso_35fd3dc2'@'10.3.156.140'

1064 - Syntax Error in SQL query near to ''wordpress-5478r34b'.* TO '_sso_67c5vh1'@'10.3.157.568'' linea 1

要么

GRANT TRIGGER ON 'wordpress'-'3236c57b'.* TO '_sso_35fd3dc2'@'10.3.156.140'

1064 - Syntax Error in SQL query near to ''wordpress'-'5478r34b'.* TO '_sso_67c5vh1'@'10.3.157.568'' linea 1

无论我做什么,它都会给我一个语法错误。

一般来说,当我在数据库中添加新数据时,我想要做的是自动求和。有更简单的方法吗?

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