我需要我的MySQL数据库在特定的coloumn中得到一些值的总和。为此,我使用了触发器语句,但MySQL给了我一个错误:
MySQL错误:#1142 - TRIGGER命令拒绝用户'XXXXXX'表wp wpdatatables 8
触发器如下:
CREATE TRIGGER SumPliche AFTER INSERT ON wp_wpdatatable_8 FOR EACH ROW UPDATE wp_wpdatatable_8 SET sommapliche = tricipite + addome + soprailiaca + sottoscapolare + ascellare + pettorale + coscia
我怎样才能做到这一点?谢谢
看来这里的问题是你的用户对wp_wpdatatable_8
数据库的权限。
要授予特定用户和数据库的触发器权限,可以使用以下命令:
mysql> GRANT TRIGGER ON <DATABASE>.* TO <USER>@'<DATABASE HOST>';
哪里
<DATABASE>
指的是包含wp_wpdatatable_8
表的数据库。<USER>
尝试发出CREATE TRIGGER
命令的用户名。<DATABASE HOST>
数据库主机。如果您在本地运行它,您可以使用localhost
。刷新权限后,创建触发器应该正常工作。
有关更多信息,请查看MySQL.documentation上的GRANT
语法
您在使用的数据库上缺少TRIGGER权限。
我做测试时遇到了这个错误。创建测试用户:
mysql> create user 'bill'@'localhost';
mysql> grant all privileges on test2.* to 'bill'@'localhost';
mysql> revoke trigger on test2.* from 'bill'@'localhost';
mysql> show grants for 'bill'@'localhost';
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Grants for bill@localhost |
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| GRANT USAGE ON *.* TO 'bill'@'localhost' IDENTIFIED BY PASSWORD '*29A1BB43D3B9EB42028B4566E4836353285B9395' |
| GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES, EXECUTE, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE, EVENT ON `test2`.* TO 'bill'@'localhost' |
+------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
现在尝试以此用户创建触发器:
~ mysql -ubill -p
mysql> use test2
mysql> create table t ( i int);
mysql> create trigger tt before insert on t for each row set new.i = 42;
ERROR 1142 (42000): TRIGGER command denied to user 'bill'@'localhost' for table 't'
我也认为你的触发器可能不会做你认为它做的事情,所以你没有创建它也是如此。
CREATE TRIGGER SumPliche AFTER INSERT ON wp_wpdatatable_8
FOR EACH ROW
UPDATE wp_wpdatatable_8
SET sommapliche = tricipite + addome + soprailiaca + sottoscapolare + ascellare + pettorale + coscia
如果我在我的测试数据库中创建此触发器(作为具有TRIGGER权限的其他用户),然后尝试插入一行:
mysql> insert into wp_wpdatatable_8 values (1, 1, 1, 1, 1, 1, 1, 1);
ERROR 1442 (HY000): Can't update table 'wp_wpdatatable_8' in
stored function/trigger because it is already used by statement which invoked
this stored function/trigger.
您可能只想在插入的行中设置值。如果是这样,您将使用NEW.*
语法引用当前行:
CREATE TRIGGER SumPliche BEFORE INSERT ON wp_wpdatatable_8
FOR EACH ROW
SET NEW.sommapliche = NEW.tricipite + NEW.addome + NEW.soprailiaca
+ NEW.sottoscapolare + NEW.ascellare + NEW.pettorale + NEW.coscia;
如果要在插入行之前更改行中的值,也必须使用BEFORE INSERT
。如果你使用AFTER INSERT
,那就太晚了。
它现在有效:
mysql> insert into wp_wpdatatable_8 values (1, 1, 1, 1, 1, 1, 1, 1);
Query OK, 1 row affected (0.02 sec)
mysql> select * from wp_wpdatatable_8;
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+
| sommapliche | tricipite | addome | soprailiaca | sottoscapolare | ascellare | pettorale | coscia |
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+
| 7 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
+-------------+-----------+--------+-------------+----------------+-----------+-----------+--------+
如果我使用
GRANT TRIGGER ON wordpress-5478r34b.* TO '_sso_67c5vh1'@'10.3.157.568'
要么
'wordpress-3236c57b'上的GRANT TRIGGER。* TO'_sso_35fd3dc2'@'10.3.156.140'
要么
GRANT TRIGGER ON 'wordpress'-'3236c57b'.* TO '_sso_35fd3dc2'@'10.3.156.140'
无论我做什么,它都会给我一个语法错误。
一般来说,当我在数据库中添加新数据时,我想要做的是自动求和。有更简单的方法吗?