我想通过单击一个按钮来切换多个div中的一个div
HTML代码
<ng-container *ngFor = "let m of images">
<button (click) = "toggle(m[m.length-1])"><img src = {{m[0]}}/></button>
<div id = "toggle" *ngIf = "chosen" [@toggle] = 'status'>
<ul>
<li *ngFor = "let z of clicked | slice: 0 : 10;"><img src = {{z}}/></li>
</ul>
</div>
<br />
</ng-container>
在* ngFor =“让m的图像中,m是数组<string[]
>并且在索引0处存储图像,并且在索引1处存储唯一ID。所以我得到函数的id,toggle()。在切换时有另一个数组<string[]
>,memberimages,有10个图像,从索引0到9,并且在最后一个索引处有unqiue id。所以将id与this.memberimages中的id进行比较,如果相同,则设置为true,并保存匹配的字符串[ ] from this.memberimages to this.clicked,用于li标签....希望解释是可以理解的.... :(
toggle(id: string){
this.status = this.status === 'open' ? 'close' : 'open';
if(this.status != 'close')
{
this.memberimages.forEach((item, index) =>{
if(item[item.length-1] == id){
this.clicked = item;
this.chosen = true;
index = this.memberimages.length;
}
});
}
else
{
this.chosen = false;
}
}
动画
animations:[
trigger('toggle', [
state('open', style({
'opacity' : '1',
'display' : 'block'
})),
state('close', style({
'opacity' : '0',
'display' : 'none'
})),
transition('open => close', animate('1000ms ease-in-out', style({
'opacity':'0',
'display' : 'none'
}))),
transition('close => open', animate('1000ms ease-in-out', style({
'opacity':'1',
'display' : 'block'
})))
])
]
div id =“toggle”的CSS只是display:none;
我期望的是,如果我单击其中一个按钮(总共5个),则应仅在该按钮下切换值。然而,实际发生的是,一旦我点击其中一个按钮,值是正确的,但每个按钮一次切换div具有相同的值,我没有看到任何动画效果我如何匹配一个div一个按钮,以便每个按钮有一个正确的值,只切换div?
PS:为我糟糕的英语道歉...... :(
试试这个
创建新变量
Toggle =[]
然后使用index来跟踪元素
<ng-container *ngFor = "let m of images; let i=index ">
<button (click) = "toggle(m[m.length-1]);Toggle[i] =! Toggles[i] "><img src = {{m[0]}}/></button>
<div id = "toggle" *ngIf = "Toggle[i]" [@toggle] = 'status'>
<ul>
<li *ngFor = "let z of clicked | slice: 0 : 10;"><img src = {{z}}/></li>
</ul>
</div>
<br />
</ng-container>