我正在编写应用程序,但我无法解决一个问题。我已经在状态中存储了用户信息(当我打开Redux DevTools时,我可以看到状态-> user: {username: name, role: ...})。)
现在在一些组件中,我想检查登录的用户是否是管理员或用户。我有它的状态,但我如何能在一些类中加载它?当我导出一个函数时,我可以使用 const userRole = useSelector(state => state.security.user.role_id);
但在班级里,它使一个问题。你能帮助我吗?
这是我的用户类的代码,我想显示DELETE按钮,只有当用户是一个管理员。
import React, {Component} from "react";
import PropTypes from "prop-types";
import {connect, useSelector} from "react-redux";
import { Link } from "react-router-dom";
import { deleteUser } from "../../store/actions/userActions";
class User extends Component{
constructor() {
super();}
onDeleteClick(id) {
this.props.deleteUser(id);
}
render() {
const { user } = this.props;
return (
<div className='row entry'>
<div className='col-sm-2'>
<span >{user.username}</span>
</div>
<div className='col-sm-2'>
<span >{user.name}</span>
</div>
<div className='col-sm-2'>
<span>{user.lastname}</span>
</div>
<div className='col-sm-2'>
<span>{user.tag}</span>
</div>
<div className='col-sm-1'>
<span>{user.pay}</span>
</div>
<div className='col-sm-1'>
<span>
{user.role_id}
</span>
</div>
<div className='col-sm-2'>
<Link to={`userlist/edituser:${user.id}`}>
<button><i className="fas fa-user-edit"></i></button>
</Link> | <button onClick={this.onDeleteClick.bind(this, user.id)}><i className="far fa-trash-alt"></i></button>
</div>
</div>
)
}
}
User.propTypes = {
deleteUser: PropTypes.func.isRequired
};
export default connect(
null, { deleteUser }
)(User);
对于类组件,你可以使用 connect
HOC与 mapStateToProps
从redux访问状态
class User extends Component{
render() {
const { user, userRole } = this.props;
...
}
}
const mapStateToProps = (state) => {
return {
useRole: state.security.user.role_id,
}
}
export default connect(
mapStateToProps, { deleteUser }
)(User);