我正在编写一个将特定字符替换为其他字符的函数
public static String makeComplement(String dna) {
if(dna.contains("A")|| (dna.contains("T") ||(dna.contains("G") ||(dna.contains("C") ) )) ){
dna = dna.replace('A' , 'T');
dna = dna.replace('T' , 'A');
dna = dna.replace('G' , 'C');
dna = dna.replace('C' , 'G');
System.out.println(dna);
}
return dna;
}
public static void main(String[] args) {
String ex ="GTACTCC";
System.out.println(ex);
makeComplement(ex);
}
它取代了A中的T和G中的C,但保持A&G不变。
当然可以。
dna = dna.replace('A' , 'T'); // replaces As with Ts
dna = dna.replace('T' , 'A'); // replace Ts with As (including the As that
// were replaced with Ts)
dna = dna.replace('G' , 'C'); // replaces Gs with Cs
dna = dna.replace('C' , 'G'); // replace Cs with Gs (including the Gs that
// were replaced with Cs)
如果你想用Cs交换As和Ts和Gs,你应该使用一些中间字母:
dna = dna.replace('A' , 'X');
dna = dna.replace('T' , 'A'); // only original Ts will become As
dna = dna.replace('X' , 'T');
dna = dna.replace('G' , 'Y');
dna = dna.replace('C' , 'G'); // only original Cs will become Gs
dna = dna.replace('Y' , 'C');
编辑:正如迈克评论的那样,如果没有replace
方法,你可以更有效地完成这个替换:
StringBuilder sb = new StringBuilder (dna.length());
for (char c : dna.toCharArray()) {
if (c == 'A')
sb.append('T');
else if (c == 'T')
sb.append('A');
else if (c == 'G')
sb.append('C');
else if (c == 'C')
sb.append('G');
}
dna = sb.toString();
调用String.contains
和/或String.replace
可能会扫描整个字符串,因此多次调用它可能会对很长的字符串造成代价。
为什么不一次完成所有替换:
// Copy the original DNA string to a new mutable char array
char[] dnaCopy = dna.toCharArray();
// Examine each character of array one time only and replace
// as necessary
for(int i = 0; i < dnaCopy.length; i++) {
if(dnaCopy[i] == 'A') {
dnaCopy[i] = 'T';
}
else if(dnaCopy[i] == 'T') {
dnaCopy[i] = 'A';
}
else if(dnaCopy[i] == 'G') {
dnaCopy[i] = 'C';
}
else if(dnaCopy[i] == 'C') {
dnaCopy[i] = 'G';
}
}
// Now you can do whatever you want with dnaCopy: make a new String, etc
对于长字符串,这种方法应该更加高效,并且可以使用分而治之的方法进行扩展(即,您可以在阵列的一半上同时处理2个线程)。