我在包含大型日志文件的文件夹中有一系列文件
-20180907 1229 debug.log -20180907 1229 system.log
我想编写一个PowerShell脚本来将它们归档。这是我的脚本:
dir *.log | % {
$archive = '"' + $_.Name + '.7z"'
$archive
$source = '"' + $_.Name + '"'
$source
&"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z $archive $source -WhatIf
}
但是,当我运行它时,我得到以下输出:
"-20180907 1229 debug.log.7z" "-20180907 1229 debug.log" 7z.exe : At C:\Users\User\Temporary\Test 7z\archive-logs.ps1:6 char:5 + &"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z $archive $source + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo : NotSpecified: (:String) [], RemoteException + FullyQualifiedErrorId : NativeCommandError Command Line Error: Unknown switch: -20180907 1229 debug.log.7z "-20180907 1229 system.log.7z" "-20180907 1229 system.log" 7z.exe : At C:\Users\User\Temporary\Test 7z\archive-logs.ps1:6 char:5 + &"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z $archive $source + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo : NotSpecified: (:String) [], RemoteException + FullyQualifiedErrorId : NativeCommandError Command Line Error: Unknown switch: -20180907 1229 system.log.7z
即使我用双引号包装文件名,它显示为7-Zip忽略双引号。
有任何想法吗?
我试过这个变种(用单引号包装文件名):
dir *.log | % {
$archive = "'" + $_.Name + ".7z'"
$archive
$source = "'" + $_.Name + "'"
$source
&"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z $archive $source
}
而这次我得到了这个输出:
'-20180907 1229 debug.log.7z' '-20180907 1229 debug.log' 7-Zip 18.05 (x64) : Copyright (c) 1999-2018 Igor Pavlov : 2018-04-30 Open archive: '-20180907 1229 debug.log.7z' -- Path = '-20180907 1229 debug.log.7z' Type = 7z Physical Size = 32 Headers Size = 0 Solid = - Blocks = 0 Scanning the drive: 7z.exe : At C:\Users\User\Temporary\Test 7z\archive-logs-B.ps1:6 char:5 + &"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z $archive $source + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo : NotSpecified: (:String) [], RemoteException + FullyQualifiedErrorId : NativeCommandError WARNING: The system cannot find the file specified. '-20180907 1229 debug.log' 0 files, 0 bytes Updating archive: '-20180907 1229 debug.log.7z' Add new data to archive: 0 files, 0 bytes Files read from disk: 0 Archive size: 32 bytes (1 KiB) Scan WARNINGS for files and folders: '-20180907 1229 debug.log' : The system cannot find the file specified. ---------------- Scan WARNINGS: 1
它创建了像'-20180907 1229 debug.log.7z'
这样的文件,但没有内容。
试试这个:
$executable = "C:\Program Files\7-Zip\7z.exe"
dir *.log | % {
$archive = "$($_.Name).7z"
$archive
$source = $_.Name
$source
$oneliner = "a",".\$($archive)",".\$($source)", "-mx4"
& $executable @oneliner
}
我认为不需要用引号括起来。 如果我做以下怎么办?
dir *.log | % { &"C:\Program Files\7-Zip\7z.exe" -mx9 a -t7z "$_.7z" $_ }