如何返回异步箭头功能？

Question

我在Redux上使用React，并具有以下代码：

hooks.js：

import { useDispatch } from 'react-redux';
import { checkCookieOne, checkCookieTwo } from './thunk';
...
export function useValidateCookieEffect() {
    const dispatch = useDispatch();
    React.useEffect(() => {
        dispatch(checkCookieOne());
        dispatch(checkCookieTwo());
    }, [dispatch]);
}

并且在我的thunk文件中：

export function checkCookieOne() {
    return async dispatch => {
        const hasCookie = Boolean(window.localStorage.getItem('cookieOne') || false);
        dispatch(store.actions.toggleCookieOneValue(hasCookie));
    };
}

export function checkCookieTwo() {
    return async dispatch => {
        const hasCookie = Boolean(window.localStorage.getItem('cookieTwo') || false);
        dispatch(store.actions.toggleCookieTwoValue(hasCookie));
    };
}

为了使其更具可读性，我想将代码合并为单行返回。

所以，来自：

export function checkCookieOne() {
    return async dispatch => {
        const hasCookie = Boolean(window.localStorage.getItem('cookieOne') || false);
        dispatch(store.actions.toggleCookieOneValue(hasCookie));
    };
}

对于这样的事情（我的尝试）-请记住，dispatch没有在此文件中声明，而仅在hooks.js中声明：

export async function checkCookieOne() => dispatch(store.actions.toggleCookieOneValue(checkGivenCookieExists('cookieOne')));

但是那是无效的语法。它抱怨箭头功能，说：

'{'或';'预期。

如何将其转换为一行？

export function checkCookieOne() { return async dispatch => dispatch(store.actions.toggleCookieOneValue(checkGivenCookieExists('cookieOne'))); }

这可以用，但不完全是我想要的

Answer 1

尝试一下

let checkCookieOne = async () => dispatch(store.actions.toggleMyCookieValue(checkGivenCookieExists('cookieOne')));

export checkCookieOne;

// Or maybe...

export let checkCookieOne = async () => dispatch(store.actions.toggleMyCookieValue(checkGivenCookieExists('cookieOne')));