我有一个元组列表。
lt = [('051623', 'O143', '1.23', '2023-05-16T18:30:00', '1M allen', 'millan'), ('051623', 'O207', '1.23', '2023-05-16T18:35:00', 'nM Mn, 4nM, 35uM Fe', 'wilo')]
需要通过逗号分隔转换为 csv 字符串,但在引号内分隔逗号时将被忽略:预期如下。
'051623','O143','1.23','2023-05-16T18:30:00','1M allen','millan'
'051623', 'O207', '1.23', '2023-05-16T18:35:00','nM Mn, 4nM, 35uM Fe','wilo'
我尝试过但不起作用:
csv_string = '\n'.join(",".join([element if element else 'None' for element in tup]) for tup in lt)
您可以使用
csv
库:
lt = [
('051623', 'O143', '1.23', '2023-05-16T18:30:00', '1M allen', 'millan'),
('051623', 'O207', '1.23', '2023-05-16T18:35:00', 'nM Mn, 4nM, 35uM Fe', 'wilo'),
]
import io
import csv
# Allows saving the csv output to a string instead of a file
f = io.StringIO(newline='')
writer = csv.writer(
f,
quotechar="'",
quoting=csv.QUOTE_ALL,
)
writer.writerows(lt)
# `getvalue()` returns a string containing the csv output
print(f.getvalue())
输出
'051623','O143','1.23','2023-05-16T18:30:00','1M allen','millan'
'051623','O207','1.23','2023-05-16T18:35:00','nM Mn, 4nM, 35uM Fe','wilo'
如果您只是尝试将行重新组合为 csv 数据,而不实际写入 CSV,则可以使用以下内容,它将用双引号将每个单独的值括起来
lines=[]
for tup in lt:
lines.append('"' + '","'.join(tup)+'"')
print(lines)
# [
# '"051623","O143","1.23","2023-05-16T18:30:00","1M allen","millan"',
# '"051623","O207","1.23","2023-05-16T18:35:00","nM Mn, 4nM, 35uM Fe","wilo"'
# ]
或者如果您只想换行包含逗号的单元格:
lines=[]
for tup in lt:
line=''
for el in tup:
if ',' in el:
el = '"'+el+'"'
line += el + ','
lines.append(line[:-1]) # Strip the extra , at the end
print(lines)
# [
# '051623,O143,1.23,2023-05-16T18:30:00,1M allen,millan',
# '051623,O207,1.23,2023-05-16T18:35:00,"nM Mn, 4nM, 35uM Fe",wilo'
# ]