Start-ChocolateyProcessAsAdmin在父文件夹中找不到脚本

问题描述 投票:0回答:1

我有这个非常基本的ChocolateyInstall.ps1脚本,应该在父文件夹中调用另一个Powershell脚本。这是我的项目结构:

project/
  service-install.ps1
  tools/
    chocolatey/
      ChocolateyInstall.ps1

这是我的ChocolateyInstall.ps1

# Install the windows service

Start-ChocolateyProcessAsAdmin -ExeToRun "powershell" -Statements "./service-install.ps1" -WorkingDirectory "..\..\"

[安装构建包时,ChocolateyInstall.ps1失败,并显示以下错误:

<S S="Error">./service-install.ps1 : The term './service-install.ps1' is not recognized as the name of a cmdlet, function, script file, or operable program. Check the spelling of the name, or if a path was included, verify that the path is correct and try again._x000D__x000A_</S>
<S S="Error">At line:7 char:9_x000D__x000A_</S>
<S S="Error">+         ./service-install.ps1_x000D__x000A_</S>
<S S="Error">+         ~~~~~~~~~~~~~~~~~~~~~_x000D__x000A_</S>
<S S="Error">    + CategoryInfo          : ObjectNotFound: (./service-install.ps1:String) [], ParentContainsErrorRecordException_x000D__x000A_</S>
<S S="Error">    + FullyQualifiedErrorId : CommandNotFoundException_x000D__x000A_</S>
<S S="Error"> _x000D__x000A_</S>

我需要使用project/目录作为工作目录来运行脚本。

为什么未正确执行/发现服务安装脚本?我已经尝试过command的示例,但仍然无法使其正常工作。

powershell chocolatey
1个回答
0
投票

在大多数Chocolatey包装中,您会看到类似以下内容的行:

$ScriptRoot = Split-Path $MyInvocation.MyCommand.Definition

这将为您提供当前正在执行的脚本的位置,即ChocolateyInstall.ps1文件。从那里,您应该能够“找到”要执行的脚本。

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