从javascript中返回的日期时间中删除NaN

Question

我正在研究yii2。在我的JavaScript中，我有一个公式，通过它可以获取一些数据。然后将数据传递到图表，然后图表将其呈现。

var arry_kwh = [];
arry_kwh = <?php echo json_encode($dataPointskWh, JSON_NUMERIC_CHECK); ?>;
var arry_kwh_diff = [];
var i = 0;
for (; i < arry_kwh.length - 1; i++) {
    arry_kwh_diff[i] = {
        label: arry_kwh[i].label + ((arry_kwh[i + 1].label - arry_kwh[i].label) / 2),
        y: (arry_kwh[i + 1].y - arry_kwh[i].y)
    };
}
console.log(JSON.stringify(arry_kwh_diff, null, 2));

返回的日志是

[
{
  "label": "2020-04-01 11:44:13NaN",
   "y": 50
},
{
  "label": "2020-04-01 11:45:49NaN",
  "y": 25
},
{
  "label": "2020-04-01 13:11:24NaN",
   "y": 25
},
{
  "label": "2020-04-02 10:19:08NaN",
   "y": 50
},
{
  "label": "2020-04-02 11:24:38NaN",
  "y": 50
},
{
  "label": "2020-04-04 12:24:38NaN",
  "y": 100
},
{
  "label": "2020-04-05 13:49:38NaN",
  "y": 50
},
{
  "label": "2020-04-05 14:36:38NaN",
  "y": 100
},
{
  "label": "2020-04-05 14:24:38NaN",
  "y": 50
},
{
  "label": "2020-04-08 09:20:41NaN",
  "y": 35
},
{
  "label": "2020-04-08 10:09:38NaN",
  "y": 55
},
{
  "label": "2020-04-08 11:35:33NaN",
  "y": 35
},
{
  "label": "2020-04-08 13:24:38NaN",
  "y": 50
}
 ]

$dataPointskWh有

Array ( [0] => Array ( [label] => 2020-04-01 11:44:13 [y] => 100 ) [1] => Array ( [label] => 2020-04-01 11:45:49 [y] => 150 ) [2] => Array ( [label] => 2020-04-01 13:11:24 [y] => 175 ) [3] => Array ( [label] => 2020-04-02 10:19:08 [y] => 200 ) [4] => Array ( [label] => 2020-04-02 11:24:38 [y] => 250 ) [5] => Array ( [label] => 2020-04-04 12:24:38 [y] => 300 ) [6] => Array ( [label] => 2020-04-05 13:49:38 [y] => 400 ) [7] => Array ( [label] => 2020-04-05 14:36:38 [y] => 450 ) [8] => Array ( [label] => 2020-04-05 14:24:38 [y] => 550 ) [9] => Array ( [label] => 2020-04-08 09:20:41 [y] => 600 ) [10] => Array ( [label] => 2020-04-08 10:09:38 [y] => 635 ) [11] => Array ( [label] => 2020-04-08 11:35:33 [y] => 690 ) [12] => Array ( [label] => 2020-04-08 13:24:38 [y] => 725 ) [13] => Array ( [label] => 2020-04-08 17:12:35 [y] => 775 ) )

如何删除日期时间中的NaN？我已经调查了这个问题，但找不到任何解决方案。

任何帮助将不胜感激。

Answer 1

您可以通过映射label属性并删除最后的3个字符来轻松完成此操作

喜欢这样

data = data.map(el => el.label.substr(0, el.label.length - 3))