如何在等距libgdx中触摸时获得瓷砖位置

Question

我正在创建2d游戏，它只是libgdx中的等距图，它是64x32

public class MyGdxGame extends ApplicationAdapter implements InputProcessor
{


    public static float zoom=0.3f;
    Texture img;
    TiledMap tiledMap;
    OrthographicCamera camera;
    TiledMapRenderer tiledMapRenderer;
    final Matrix4 matrix = new Matrix4();
    public static float lastx,lasty;
    private IsometricTiledMapRenderer renderer;
    SpriteBatch sb;
    Texture texture;
    Sprite sprite;


    TextureRegion textureRegion;

    public static float translate,pick;



    TiledMapTileLayer.Cell cell;
    TiledMapTileLayer tileLayer;

    @Override
    public void create () {
        float w = Gdx.graphics.getWidth();
        float h = Gdx.graphics.getHeight();

        camera = new OrthographicCamera();
        camera.setToOrtho(false,w,h);
        tiledMap = new TmxMapLoader().load("iso.tmx");//iso
        renderer = new IsometricTiledMapRenderer(tiledMap);
        camera = new OrthographicCamera(Gdx.graphics.getWidth(), Gdx.graphics.getHeight());




        camera.update();


        Gdx.input.setInputProcessor(this);

        sb = new SpriteBatch();
        texture = new Texture(Gdx.files.internal("sand_128x64.png"));
        sprite = new Sprite(texture);
        sprite.setSize(50,50);



        int mapWidth = tiledMap.getProperties().get("width",Integer.class);
        int mapHeight = tiledMap.getProperties().get("height",Integer.class);



    }

    @Override
    public void render () {
        Gdx.gl.glClearColor(.5f, .7f, .9f, 1);
        Gdx.gl.glBlendFunc(GL20.GL_SRC_ALPHA, GL20.GL_ONE_MINUS_SRC_ALPHA);
        Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
        camera.zoom = zoom;




        camera.update();
        renderer.setView(camera);
        renderer.render();

        sb.setProjectionMatrix(camera.combined);
        sb.begin();
        //sprite.draw(sb);

        sb.end();



    }



    @Override
    public boolean touchDown(int screenX, int screenY, int pointer, int button) {




        lastx=-screenX;
        lasty=screenY;
        Vector3 clickCoordinates = new Vector3(screenX,screenY,0);
        Vector3 position = camera.unproject(clickCoordinates);
        //sprite.setPosition(position.x, position.y);
        translate=position.x;
        return false;
    }

    @Override
    public boolean touchUp(int screenX, int screenY, int pointer, int button) {
        lastx=0;
        lasty=0;
        return false;
    }

    @Override
    public boolean touchDragged(int screenX, int screenY, int pointer) {

        if (lastx != 0) {
            camera.translate(-screenX - lastx, screenY - lasty);
            lastx = -screenX;
            lasty = screenY;


        }

        return false;
    }

    @Override
    public boolean mouseMoved(int screenX, int screenY) {

        return false;
    }

    @Override
    public boolean scrolled(int amount) {

        return false;
    }

    @Override
    public boolean keyDown(int p1)
    {
        // TODO: Implement this method
        return false;
    }

    @Override
    public boolean keyUp(int p1)
    {
        // TODO: Implement this method
        return false;
    }

    @Override
    public boolean keyTyped(char p1)
    {
        // TODO: Implement this method
        return false;
    }

}

现在我想在触摸时选择贴砖，所以我得到了贴砖（x，y），我尝试了很多方法来做到这一点，但是我找不到很好的解决方案，所以我尝试了此]]

LibGDX: How to make tiled map tiles clickable?

但是它没有用，那我该怎么办？

我正在创建2D游戏，它只是libgdx中的等距图，它是64x32公共类MyGdxGame扩展了ApplicationAdapter实现InputProcessor {public static float zoom = 0.3f;纹理...

Answer 1

问题是，等轴测图是旋转的正方形，因此您无法放置可点击的正方形