构建井字游戏，但如果玩家二号在已填写的行中做了错误的回合，则该回合将被跳过，我该如何解决此问题？

Question

首先，我对编码还是新手，所以请不要因为我没有做正确的事情而责备我。代码中的所有内容都是我迄今为止从课堂上学到的。

所以我构建了一个井字游戏，正如标题所示，如果棋盘上填满了整行，则玩家二号的回合将被跳过。

代码主要部分：

print("This is Tic-Tac-Toe, play this with a friend")
TicTacToe = [["-", "-", "-"], 
             ["-", "-", "-"], 
             ["-", "-", "-"]]

for row in TicTacToe:
    print(row[0],row[1],row[2])

while True:
    Player = input("Which row do you want to go; T = top, M = middle, or B = bottom?\n")

    if Player not in ["top", "Top", "T", "t", "middle", "Middle", "M", "m", "bottom", "Bottom", "B", "b"]:
        print("Wrong input, I'm afraid you are going to have to actually write what you were told to.")
        continue
    
    # These are the moves of the player, starting with Player One.

    if Player == "top" or Player == "Top" or Player == "T" or Player == "t":
        while True:
            Movement = input("Where do you want to go, L = left, M = middle or R = right?\n")
        # Checks if the movement after the player chose their option is in check
            if Movement not in ["left", "Left", "L", "l", "Middle", "middle", "M", "m", "right", "Right", "R", "r"]:
                print("That is not one of the options you are allowed to write, please write the options listed.")
                continue

            if Movement == "left" or Movement == "Left" or Movement == "L" or Movement == "l":
                if TicTacToe[0][0] == "-":
                    TicTacToe[0][0] = "X"
                    break
                else:
                    print("A move has already been placed there!")

    # Now it is the beginning of Player Two's turn

    while True: 
        Player2 = input("Now it's your turn Player Two; T = top, M = middle, or B = bottom?\n")
        
        # This is what happens if Player Two does not input the options originally listed

        if Player2 not in ["top", "Top", "T", "t", "middle", "Middle", "M", "m", "bottom", "Bottom", "B", "b"]:
            print("Wrong input, I'm afraid you are going to have to actually write what you were told to.")
            continue
        
        # Moves of Player Two

        if Player2 == "top" or Player2 == "Top" or Player2 == "T" or Player2 == "t":
            while True:
                Movement = input("Where do you want to go, L = left, M = middle or R = right?\n")
            # Checks if the movement after the player chose their option is in check
                if Movement not in ["left", "Left", "L", "l", "Middle", "middle", "M", "m", "right", "Right", "R", "r"]:
                    print("That is not one of the options you are allowed to write, please write the options listed.")
                    continue
                
                if Movement == "left" or Movement == "Left" or Movement == "L" or Movement == "l":
                    if TicTacToe[0][0] == "-":
                        TicTacToe[0][0] = "O"
                        break
                    else:
                        print("A move has already been placed there!")
                        break

因此，在玩家二号的代码块以及其他类似的代码块中，我尝试将 else 标签下的中断更改为 continue 语句，认为它会循环到原来的问题“现在轮到玩家二号了； T = 顶部，M = 中间，还是 B = 底部？”。

代码块：

                if Movement == "left" or Movement == "Left" or Movement == "L" or Movement == "l":
                if TicTacToe[0][0] == "-":
                    TicTacToe[0][0] = "O"
                    break
                else:
                    print("A move has already been placed there!")
                    break

更改的代码块：

                if Movement == "left" or Movement == "Left" or Movement == "L" or Movement == "l":
                if TicTacToe[0][0] == "-":
                    TicTacToe[0][0] = "O"
                    break
                else:
                    print("A move has already been placed there!")
                    continue

相反，它会循环回到名为“Movement”的变量，这使得玩家两个软锁定，因为该行已完全填满。

如果有人知道如何解决此问题，请同时解释为什么我的方法不起作用以及新方法如何工作。

Answer 1

您需要调整代码中的逻辑。在打印“移动已被放置在那里！”后，不要使用

continue

。对于玩家二，您可以简单地打破循环的当前迭代并允许玩家二进行另一次移动。

考虑以下内容（请记住，我不使用 python，我的代码中也可能存在问题）：

if Movement == "left" or Movement == "Left" or Movement == "L" or Movement == "l":
    if TicTacToe[0][0] == "-":
        TicTacToe[0][0] = "O"
        break
    else:
        print("A move has already been placed there!")
        break  # Break out of the current iteration to allow Player Two to make another move

使用

continue

无法按预期工作的原因是

continue

会跳过内循环中的剩余代码并继续该循环的下一次迭代。由于内循环中没有更多的迭代，因此不会达到预期的效果。

通过在打印消息后使用

break

，您可以退出内循环，从而允许再次提示玩家二进行移动。这样，控制流返回到外循环，玩家二可以再进行一次移动。