当我在第5个块中分配out_of_marks_limit = True
时,我希望if语句的第一个块为“True”,并且我不希望代码循环或再询问用户。
在其他编程语言中,缩进用于使程序看起来很好。但是因为python只检查第一个块到相同缩进的条件,所以我不能将2个代码块的布尔值分配给第一个块。 This is what I'm trying to say.
我是一名中级程序员,这个程序仅用于练习目的。
a = int(input("Enter no. of subjects: "))
count = 1
d = 0
out_of_marks_limit = False #I want the out_of_limit to be True
if a <= 10:
if not out_of_marks_limit:
if count <= a:
for c in range(a):
b = float(input("Enter mark of subject " + str(count) + ": "))
if b <= 100: #If this condition went false then it will skip to else statement
d += b
count += 1
if count > a:
cal = round(d/a, 2)
print("Your percentage is " + str(cal) + "%")
else:
out_of_marks_limit = True #So this boolean value should passed to the first line of code
print("Marks enter for individual subject is above 100")
else:
print("Subject limit exceeded")
我希望输出打印(“单个主题的标记输入超过100”),如果out_of_marks_limit为True并且不想再循环
我认为您可以使用while循环来检查out_of_marks_limit条件:
a = int(input("Enter no. of subjects: "))
count = 1
d = 0
out_of_marks_limit = False #I want the out_of_limit to be True
while not out_of_marks_limit:
if a <= 10:
if not out_of_marks_limit:
if count <= a:
for c in range(a):
b = float(input("Enter mark of subject " + str(count) + ": "))
if b <= 100: #If this condition went false then it will skip to else statement
d += b
count += 1
if count > a:
cal = round(d/a, 2)
print("Your percentage is " + str(cal) + "%")
else:
out_of_marks_limit = True #So this boolean value should passed to the first line of code
print("Marks enter for individual subject is above 100")
else:
print("Subject limit exceeded")