分成新列

Question

为了将单元格拆分为新列，我使用以下代码：

   | Column1       | Column2
   | a;b;c;d;e;f   | 1;2;3;4

df = pd.read_excel('FileName.xlsx')
new = df["Column1"].str.split(";", n=5, expand=True).
df['1st'] = new[0]
df['2nd'] = new[1]
df['3rd'] = new[2]
df['4th'] = new[3]
df['5th'] = new[4]
df['6th'] = new[5]
df.drop(columns=["Column1"], inplace=True)

输出将变为

 Column:   1st 2nd 3rd 4th 5th 6th 
             a   b   c   d   e   f;

为了取消最后一项中的分号，我该怎么办

Answer 1

您很可能在提问中打错了字。我敢打赌，当您读入数据时，

f后面会有一个分号，并且它看起来像这样：

    Column1         Column2
0   a;b;c;d;e;f;    1;2;3;4

和
not此：
    Column1         Column2
0   a;b;c;d;e;f     1;2;3;4

因此，如果将n=6设置为n=5，则应删除最后的分号。复制我包含在上面答案中的第一个数据帧，并使用下面的df = pd.read_clipboard('\s+\s+')运行下面的代码：
import pandas as pd
df = pd.read_clipboard('\s+\s+')
new = df["Column1"].str.split(";", n=6, expand=True)
df['1st'] = new[0]
df['2nd'] = new[1]
df['3rd'] = new[2]
df['4th'] = new[3]
df['5th'] = new[4]
df['6th'] = new[5]
df.drop(columns=["Column1", "Column2"], inplace=True)
df