我想根据传入的参数使用多个 where 子句查询 Firestore 数据库。以下代码块有效:
getProducts2(accountId: string, manufacturer?: string, materialType?: string): Promise<Product[]> {
return new Promise<Product[]>((resolve, reject) => {
const productCollection2: AngularFirestoreCollection<FreightRule> = this.afs.collection('products');
const query = productCollection2.ref
.where('materialType', '==', materialType)
.where('manufacturer', '==', manufacturer);
query.get().then(querySnapshot => {
if (querySnapshot.size > 0) {
const data = querySnapshot.docs.map(documentSnapshot => {
return documentSnapshot.data();
}) as Product[];
resolve(data);
} //todo else...
});
});
}
但我真正想做的是根据可选参数有条件地包含 where 子句。以下是我想要的,但它不起作用:
getProducts2(accountId: string, manufacturer?: string, materialType?: string): Promise<Product[]> {
return new Promise<Product[]>((resolve, reject) => {
const productCollection2: AngularFirestoreCollection<FreightRule> = this.afs.collection('products');
const query = productCollection2.ref;
if (manufacturer) {
query.where('manufacturer', '==', manufacturer);
}
if (materialType) {
query.where('materialType', '==', materialType);
}
query.get().then(querySnapshot => {
if (querySnapshot.size > 0) {
const data = querySnapshot.docs.map(documentSnapshot => {
return documentSnapshot.data();
}) as Product[];
resolve(data);
} //todo else...
});
});
}
虽然有效,但此代码仅返回所有产品,不进行任何过滤。
有没有办法构建这个结构,以便我可以根据可选参数进行过滤?
编辑:我意识到我可以做类似的事情:
let query;
if (manufacturer && materialType) {
query = productCollection2.ref.where(....).where(....)
} else if (manufacturer) {
query = productCollection2.ref.where(....)
} else if (materialType) {
query = productCollection2.ref.where(....)
}
我只是希望有一些更优雅的东西。
基于先前的查询,不要重复先前的查询:
let query = collection // initial query, no filters
if (condition1) {
// add a filter for condition1
query = query.where(...)
}
if (condition2) {
// add a filter for condition2
query = query.where(...)
}
// etc
如果使用不同的查询结构,您可以尝试以下方式:
db.collection("subscriptions").where("email", '==', req.body.email,"&&","subscription_type","==","free").get();
或
db.collection("subscriptions").where("email", '==', req.body.email).where("subscription_type", '==', 'free111').get();