如何在请求python中调用post api？

Question

我有一个采用三个参数的API，两个是字符串，而第三个是名为“ content”的文件。

from datetime import date

AuthToken = "xxxxxxxxxxx"
fileName = "a.txt"
FolderID = "xxxxxxxxxxx"
myfiles = {'file': ('report.xls', open('C:\\Users\\Nawaf Momin\\Desktop\\a.xls', 'rb'), 'application/vnd.ms-excel', {'Expires': '0'})}
URL = "https://apidocs.zoho.com/files/v1/upload?authtoken=" + AuthToken + "&scope=docsapi"
mydata = {
    'filename': fileName,
    'fid': FolderID,
    'content': myfiles
}
r = requests.post(url=URL, data=mydata)
print(r.status_code)
print(r.text)

有关api文档，请访问：https://www.zoho.com/docs/zoho-docs-api.html其上传帖子api ..

Answer 1

您没有指出要获取的错误，所以我认为文件内容没有显示出来。您可能应该单独放置文件内容并向其添加标头，并且您还需要安装和导入请求库，因为它不是内置的。

from datetime import date
import requests

headers = {
"User-Agent":"Mozilla/5.0" #you will need to complete this user agent yourself
}

AuthToken = "xxxxxxxxxxx"
fileName = "a.txt"
FolderID = "xxxxxxxxxxx"
myfiles = {'file': ('report.xls', open('C:\\Users\\Nawaf Momin\\Desktop\\a.xls', 'rb'), 'application/vnd.ms-excel', {'Expires': '0'})}
URL = "https://apidocs.zoho.com/files/v1/upload

params = {
authtoken":AuthToken,
"scope":"docsapi"
}

r = requests.post(url=URL,  params=params, files=myfile, headers=headers)
print(r.status_code)
print(r.text)

希望这有所帮助

Answer 2

我解决了。myfiles = {'file': ('report.xls', open('C:\\Users\\Nawaf Momin\\Desktop\\a.xls', 'rb'), 'application/vnd.ms-excel', {'Expires': '0'})}在这里，我发送的是parameter_name，而不是file。所以现在看起来像myfiles = {'parametername': ('report.xls', open('pathToFile', 'rb'), 'application/vnd.ms-excel', {'Expires': '0'})}