如何获得Keras中深RNN的所有中间层的输出

问题描述 投票:0回答:2

我正在尝试获取Keras中自定义RNN模型每一层的输出。该模型的代码如下。

from tensorflow.python import keras
from tensorflow.python.keras import backend as K
from tensorflow.python.keras.layers import RNN, Dense, Activation
from tensorflow.python.keras.models import Model
import numpy as np


class MinimalRNNCell(keras.layers.Layer):

    def __init__(self, units, **kwargs):
        self.units = units
        self.state_size = units
        super(MinimalRNNCell, self).__init__(**kwargs)

    def build(self, input_shape):
        self.kernel = self.add_weight(shape=(input_shape[-1], self.units),
                                      initializer='uniform',
                                      name='kernel')
        self.recurrent_kernel = self.add_weight(
            shape=(self.units, self.units),
            initializer='uniform',
            name='recurrent_kernel')
        self.built = True

    def call(self, inputs, states):
        prev_output = states[0]
        h = K.dot(inputs, self.kernel)
        output = h + K.dot(prev_output, self.recurrent_kernel)
        return output, [output]


cells = [MinimalRNNCell(32), MinimalRNNCell(64)]
x = keras.Input((None, 257))
y = RNN(cells)(x)
out = Dense(257, name='fin_dense')(y)
out = Activation('sigmoid', name='out_layer')(out)

model = Model(inputs=x, outputs=out)

我可以使用得到预测,

in_test = np.random.randn(1, 3, 257)
mod_out = model.predict(in_test)

但是我想要每个图层的输出,当我尝试使用适用于所有其他Keras模型的getLayerOutputs函数时>

def getLayerOutputs(model, input_data, learning_phase=1):
    outputs = [layer.output for layer in model.layers[1:]] # exclude Input
    layers_fn = K.function([model.input, K.learning_phase()], outputs)
    return layers_fn([input_data, learning_phase])

layer_outs = getLayerOutputs(model, in_test)

我获得整个RNN层的输出,而不是其中的每个单元的输出,如何使用RNN获得每个单元的输出?

我正在尝试获取Keras中自定义RNN模型每一层的输出。该模型的代码如下。从tensorflow.python导入keras从tensorflow.python.keras导入后端...

python tensorflow keras recurrent-neural-network
2个回答
0
投票

这应该在tensorflow 1.x(测试版本1.12.0)上执行:


0
投票

通过像这样将return_state标志更改为True

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