将提琴手原始标题转换为curl -X post命令

问题描述 投票:-1回答:1

我有我用提琴手检查过的原始标题数据

这是我从提琴手的检查中获得的原始标头数据

POST /devices/discover/ HTTP/1.1
Host: 192.168.1.40:3579
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:72.0) Gecko/20100101 Firefox/72.0
Accept: application/json, text/plain, */*
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Content-Type: application/json;charset=utf-8
Content-Length: 47
Origin: http://192.168.1.40
DNT: 1
Connection: keep-alive
Referer: http://192.168.1.40/

并且当我在提琴手作曲家中执行它时,它可以工作,但是当我尝试将其转换为curl -X POST命令时,什么也没有发生。

这是我与提琴手发送的原始数据

POST http://192.168.1.40:3579/devices/discover/ HTTP/1.1
Host: 192.168.1.40:3579
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:72.0) Gecko/20100101 Firefox/72.0
Accept: application/json, text/plain, */*
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Content-Type: application/json;charset=utf-8
Content-Length: 47
Origin: http://192.168.1.40
DNT: 1
Connection: keep-alive
Referer: http://192.168.1.40/

{"switchDiscovery":true,"silentDiscovery":true}

但是我希望通过从终端发送某种curl -X POST命令来开始工作

curl postman fiddler
1个回答
0
投票

在Fiddler中,您可以在会话列表中选择请求会话,然后使用File -> Export -> Selected Sessions -> cURL script。这将生成.bat文件,其中包含带有所需参数的curl调用。

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