“ PDF拆分后文件未打开以供读取” Flask

问题描述 投票:0回答:1

我正在尝试拆分作为对此Flask API的发布请求而获得的PDF文件。我正在使用PyPDF2处理pdf文件,尝试发布刚拆分的pdf时遇到此错误:“ IOError:文件未打开以供读取”。我尝试在帖子之前再次打开它,但这会导致另一种错误。

from flask import render_template, request
from app import app
from PyPDF2 import PdfFileWriter, PdfFileReader
import requests


@app.route('/')
def start():
    return render_template('home.html')


#upload-route
@app.route('/upload', methods = ['POST'])
def upload():
    pdf_data = None 
    split_pages = []
    if 'pdf' in request.files:
        incoming_pdf = request.files['pdf']
        pdf_data = PdfFileReader(incoming_pdf, 'rb') 
        for i in range(pdf_data.numPages):
            output = PdfFileWriter()
            output.addPage(pdf_data.getPage(i))
            with open("document-page%s.pdf" % i, "wb").read() as outputStream:
            ##new_page = output.write(outputStream)
                try:
                    split_pages.append(output)
                    print('Created: {}'.format("document-page%s.pdf" % i))
                    files  = {'userfile': outputStream }
                    upload_url ='*URL IM POSTING TO*'
                    auth_upload={
                        *AUTH KEYS*
                    }
                    r=requests.post(url=upload_url, files=files,data=auth_upload)
                finally:
                    outputStream.close()

    else:
        return "please upload a file to process"

我知道这可能是一个非常基本的问题,但是我花了很多时间在此上,我不再直白了。

python api flask python-requests
1个回答
0
投票

我刚刚看过您的代码,那又如何?

from PyPDF2 import PdfFileWriter, PdfFileReader

with open('./reklamacja.pdf', 'rb') as my_pdf:
    pdf_data = PdfFileReader(my_pdf) 
    for i in range(pdf_data.numPages):
        output = PdfFileWriter()
        # output.addPage(pdf_data.getPage(i))
        output.insertPage(pdf_data.getPage(i))
        filename = "document-page%s.pdf" % i
        with open(filename, "wb") as outputStream:
            output.write(outputStream)

        with open(filename, 'rb') as file_to_send:
            r = requests.post('http://someurl.bin', files={'myname': file_to_send})


        { Some other code...}

将其内置到flask代码中,它应该可以工作。对我来说,您只是在'try'块中稍微复杂了一点:)希望这能解决您的问题。

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