无法使用jinja访问字典的值

Question

这是我的观点.py

def following(request):
    currentUser = User.objects.get(pk=request.user.id)
    currentUser_followings = Following_System.objects.get(user=currentUser).following
    allPosts = Post.objects.all().order_by("-timestamp").reverse()
    followingPosts = []
    for user in currentUser_followings.all():
        for post in allPosts:
            if post.author == user:
                followingPosts.append(post)
    
    **post_likers_ids = {post.id: list(post.likers.values_list('id', flat=True)) for post in followingPosts}**

    # Show 10 posts per page.
    paginator = Paginator(followingPosts, 5) 
    page_number = request.GET.get('page')
    page_obj = paginator.get_page(page_number)
    return render(request, "network/following.html",{
        "page_obj": page_obj,
        "post_likers_ids" : post_likers_ids
    })

我调试，post_likers_ids 返回：({4: [2], 2: [1,3,5]}) 现在在我的以下 html 中，为什么 if 条件总是 false （尽管对于某些人来说应该是 true，因为我知道预期的输入输出）：

        {% for post in page_obj %}
        <div class="list-group-item">
            {% with post_id=post.id %}
                {% if user.id in post_likers_ids.post_id %}
                  <p>The user liked this </p>
                {% else %}
                  <p>The user have not liked this </p>
                {% endif %}
            {% endwith %}
        </div>
        {% endfor %}

这是我的模型，如果有帮助的话：

class Post(models.Model):
    content = models.TextField(blank=False)
    author = models.ForeignKey("User", on_delete=models.CASCADE, related_name="author")
    timestamp = models.DateTimeField(auto_now_add=True)
    likers = models.ManyToManyField("User", related_name="liked_posts", blank=True)

    def serialize(self):
        likes_count = self.likers.count()  #
        likers = [user.id for user in self.likers.all()]
        
        return {
            "id": self.id,
            "content": self.content,
            "author": self.author.username,
            "author_id": self.author.id,
            "timestamp": self.timestamp.strftime("%b %d %Y, %I:%M %p"),
            "likes": likes_count,
            "likers" : likers,
        }

好像用的是jinja模板，

post_likers_ids.post_id

行为怪异，例如，当 post_id = 4 时；使用

post_likers_ids.4

返回正确的值，但使用 post_likers_ids.post_id 返回空

Answer 1

您可能会通过以下方式检查：

{% if user.id in post_likers_ids[post_id] %}
    <!-- … -->
{% endif %}

但是构建这样的字典本身效率不高，因为它会触发n查询n帖子。