我有一个如下所示的单行数据框:
Donor Treatment Timepoint
MK434_016 WT5 ST002_50uM 6hr
还有一个字符串,如下所示:
[1] "AAACAAGCAAACAAGAATTCGGTT-1" "AAACAAGCAAACAATCATTCGGTT-1" "AAACAAGCAAACCTGAATTCGGTT-1" "AAACAAGCAAACTTGGATTCGGTT-1"
[5] "AAACAAGCAAAGACCCATTCGGTT-1" "AAACAAGCAAAGGTAAATTCGGTT-1"
我想将两者合并以创建一个如下所示的数据框:
Donor Treatment Timepoint
AAACAAGCAAACAAGAATTCGGTT-1 WT5 ST002_50uM 6hr
AAACAAGCAAACAATCATTCGGTT-1 WT5 ST002_50uM 6hr
AAACAAGCAAACCTGAATTCGGTT-1 WT5 ST002_50uM 6hr
etc...
我尝试使用 rbind() 或 Paste() 以几种不同的方式合并它们,但不知道如何获取我正在寻找的完整数据帧。
我首先将它们连接在一起,没有行名称,因为有些工具尊重它们,有些工具忽略它们,有些工具主动删除它们。
df2 <- cbind(df1[rep(1, length(strings)),], data.frame(barcode = strings))
df2
# Donor Treatment Timepoint barcode
# MK434_016 WT5 ST002_50uM 6hr AAACAAGCAAACAAGAATTCGGTT-1
# MK434_016.1 WT5 ST002_50uM 6hr AAACAAGCAAACAATCATTCGGTT-1
# MK434_016.2 WT5 ST002_50uM 6hr AAACAAGCAAACCTGAATTCGGTT-1
# MK434_016.3 WT5 ST002_50uM 6hr AAACAAGCAAACTTGGATTCGGTT-1
# MK434_016.4 WT5 ST002_50uM 6hr AAACAAGCAAAGACCCATTCGGTT-1
# MK434_016.5 WT5 ST002_50uM 6hr AAACAAGCAAAGGTAAATTCGGTT-1
从这里开始,如果您确实想从列中删除
barcode
信息并将其设为行名称,那么这很简单:
rownames(df2) <- df2$barcode
df2$barcode <- NULL
df2
# Donor Treatment Timepoint
# AAACAAGCAAACAAGAATTCGGTT-1 WT5 ST002_50uM 6hr
# AAACAAGCAAACAATCATTCGGTT-1 WT5 ST002_50uM 6hr
# AAACAAGCAAACCTGAATTCGGTT-1 WT5 ST002_50uM 6hr
# AAACAAGCAAACTTGGATTCGGTT-1 WT5 ST002_50uM 6hr
# AAACAAGCAAAGACCCATTCGGTT-1 WT5 ST002_50uM 6hr
# AAACAAGCAAAGGTAAATTCGGTT-1 WT5 ST002_50uM 6hr
数据
df1 <- structure(list(Donor = "WT5", Treatment = "ST002_50uM", Timepoint = "6hr"), class = "data.frame", row.names = "MK434_016")
strings <- c("AAACAAGCAAACAAGAATTCGGTT-1", "AAACAAGCAAACAATCATTCGGTT-1", "AAACAAGCAAACCTGAATTCGGTT-1", "AAACAAGCAAACTTGGATTCGGTT-1", "AAACAAGCAAAGACCCATTCGGTT-1", "AAACAAGCAAAGGTAAATTCGGTT-1")