Flink与Guava缓存 - ProcessFunction的实现不可序列化

问题描述 投票:0回答:1

我实现了一个ProcessFunction,它使用Guava缓存来过滤传入事件流。代码如下所示:

object myJob {
 private def updateCache(cacheObject, someValue) = {}
 private def getCacheValue(cacheObject, someKey) = {}

 override def run(params, executionEnv) = {
  val inputStream = executionEnv.stream

  val c = CacheBuilder.newBuilder()

  val outStream = inputStream.process(new ProcessFunction() { 
    updateCache()
    getCacheValue} 
    )
 }
}

在向Flink提交作业时,我收到以下错误:

Caused by: org.apache.flink.api.common.InvalidProgramException: The implementation of the ProcessFunction is not serializable. The object probably contains or references non serializable fields.
at org.apache.flink.api.java.ClosureCleaner.clean(ClosureCleaner.java:99)
at org.apache.flink.streaming.api.environment.StreamExecutionEnvironment.clean(StreamExecutionEnvironment.java:1560)
at org.apache.flink.streaming.api.datastream.DataStream.clean(DataStream.java:185)
at org.apache.flink.streaming.api.datastream.DataStream.process(DataStream.java:666)
at org.apache.flink.streaming.api.scala.DataStream.process(DataStream.scala:686)

我知道我做错了什么?如何解决此序列化错误?

scala serialization guava apache-flink flink-streaming
1个回答
0
投票

该错误基本上表示您依赖于Flink无法序列化的Object。在您显示的情况下,将加载项标记为惰性的字段应该可以解决问题:

   lazy val c = CacheBuilder.newBuilder()

一般来说,在这种情况下,你应该参考Flink的documentation,它解释了这个问题

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