XTS to.weekly返回不同的每周端点

问题描述 投票:3回答:1

我有一个问题,即在endpoints()xts功能(以及to.weekly功能,它使用端点)有时会返回周五本周结束,有时返回周一。

我的数据集被称为sp2

> head(sp2)
           [,1]
2012-01-09 1.78
2012-01-10 1.78
2012-01-11 1.77
2012-01-12 1.80
2012-01-13 1.77
2012-01-16 1.77

> tail(sp2)
           [,1]
2012-06-28 1.94
2012-06-29 1.92
2012-07-02 1.92
2012-07-03 1.90
2012-07-04 1.89
2012-07-05 1.89

> class(sp2)
[1] "xts" "zoo"

> weekdays(index(sp2))
  [1] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [11] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [21] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [31] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [41] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [51] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [61] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [71] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [81] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
 [91] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
[101] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
[111] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"   
[121] "Monday"    "Tuesday"   "Wednesday" "Thursday"  "Friday"    "Monday"    "Tuesday"   "Wednesday" "Thursday" 

因此,大家可以看到有数据系列没有丢失工作日。

然而.....

> weekdays(index(to.weekly(sp2)))
 [1] "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Friday"   "Monday"  
[12] "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"  
[23] "Monday"   "Monday"   "Monday"   "Thursday"

当然这应该是周五(除了最后一点也就是今天,周四)?

我在做什么错在这里,而且有一种解决方法?

我希望计算上周五至周五该数据连续数周的变化。

..........................................重复的例子...... ..................

i <- as.Date((as.numeric(Sys.Date())-200):as.numeric(Sys.Date()))
x <- xts(rep(1, length(i)), order.by = i)
weekdays(index(to.weekly(x)))
#  [1] "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"  
# [14] "Sunday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"   "Monday"  
# [27] "Monday"   "Monday"   "Monday"   "Thursday"
y <- xts(rep(1, length(i)), order.by = as.POSIXct(i))
weekdays(index(to.weekly(y)))
# [1] "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"  
# [14] "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"   "Sunday"  
# [27] "Sunday"   "Sunday"   "Sunday"   "Thursday"
r xts zoo
1个回答
3
投票

这是已被固定在R-伪造CRAN版中的错误。基本上,该指数的时间部分没有被丢弃,你遇到了一些时髦的业务时区和夏令时。

Install from R-Forge使用校正功能。

require(xts)
i <- Sys.Date()+200:0
x <- xts(rep(1, length(i)), order.by = i)
y <- xts(rep(1, length(i)), order.by = as.POSIXct(i))
all.equal(weekdays(index(to.weekly(x))), weekdays(index(to.weekly(y))))
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