我需要计算角度的变化并将其存储在数组中,我遇到以下问题: 角度通过计算增加其值,当角度值优于 90° 时,python 开始绘制补充值,而不是延续值,如下所示:
不良方式(并且正在发生): 23.45°、26.7°、...、84.5°、88.33°、85°、82.3°...
理想的方式: 23.45°、26.7°、...、84.5°、88.33°、91.2°、94.7°...
我的代码是:
import math as mt
import numpy as np
l = 85
s = 170
q = 30.07
p = 120
theta = (3.81*np.pi)/180
alfa = np.linspace((104.07*np.pi)/180, (26.19*np.pi)/180, 40)
d = np.sqrt(s**2 + q**2 - 2*s*q*np.cos(alfa))
gama = np.arccos((l**2 + p**2 - s**2 - q**2 + 2*s*q*np.cos(alfa))/(2*l*p))
betalinha = np.arcsin((s / d) * np.sin(alfa))*180/np.pi
print(np.around(betalinha, 2))
输出: [66.59 68.46 70.34 72.22 74.12 76.03 77.95 79.88 81.82 83.77 85.74 87.72 89.7 88.29 86.28 84.25 82.21 80.16 78.09 76.01 73.92 71.81 69.69 67.55 65.4 63.23 61.05 58.86 56.65 54.43 52.2 49.95 47.68 45.41 43.12 40.82 38.5 36.18 33.84 31.49]
我不确定根本问题是什么,但我相信你可以通过
纠正它betalinha
# Compute the diff (adding a dummy value to the beginning since diff returns an array of N - 1 length)
diff = np.insert(np.diff(betalinha), 0, 1)
# Reset positive values to 0
diff[diff > 0] = 0
# Fix decreasing values
betalinha -= diff.cumsum() * 2
输出:
>>> betalinha
array([ 66.59, 68.46, 70.34, 72.22, 74.12, 76.03, 77.95, 79.88,
81.82, 83.77, 85.74, 87.72, 89.7 , 91.11, <--- 93.12, 95.15,
97.19, 99.24, 101.31, 103.39, 105.48, 107.59, 109.71, 111.85,
114. , 116.17, 118.35, 120.54, 122.75, 124.97, 127.2 , 129.45,
131.72, 133.99, 136.28, 138.58, 140.9 , 143.22, 145.56, 147.91])
diff = np.insert(np.diff(betalinha), 0, 1)
while j < len(diff):
if diff[j] < 0:
betalinha[j] -= np.pi
betalinha[j] *= -1
j+=1
输出:
[1.16218675, 1.19480394, 1.22758774, 1.26054302, 1.29367464,
1.32698746, 1.36048627, 1.39417585, 1.42806092, 1.46214611,
1.49643599, 1.53093502, 1.56564752, 1.60057772, 1.63572963,
1.67110713, 1.70671387, 1.74255327, 1.7786285, 1.81494244,
1.85149766, 1.88829639, 1.92534047, 1.96263135, 2.00017004,
2.03795707, 2.07599248, 2.11427574, 2.15280579, 2.19158094,
2.23059888, 2.26985664, 2.30935057, 2.34907629, 2.38902871,
2.42920199, 2.46958953, 2.51018397, 2.55097717, 2.59196023]