我有一个pandas数据帧df,其中id为字符串:我正在尝试创建new_claim和new_description列
最近的SO我发现是Efficiently replace part of value from one column with value from another column in pandas using regex?但这使用拆分部分,并且由于描述的变化,我无法概括。
我可以跑一次
date_reg = re.compile(r'\b'+df['old_id'][1]+r'\b')
df['new_claim'] = df['claim'].replace(to_replace=date_reg, value=df['external_id'], inplace=False)
但如果我有
date_reg = re.compile(r'\b'+df['claim']+r'\b')
然后我得到“TypeError:'系列'对象是可变的,因此它们不能被散列”
我采取的另一种方法
df['new_claim'] = df['claim']
for i in range(5):
old_id = df['old_id'][i]
new_id = df['external_id'][i]
df['new_claim'][i] = df['claim'][i].replace(to_replace=old_id,value=new_id)
给出了TypeError:replace()不带关键字参数
仅使用pandas.replace()方法:
df.old_id = df.old_id.fillna(0).astype('int')
list_old = list(map(str, df.old_id.tolist()))
list_new = list(map(str, df.external_id.tolist()))
df['new_claim'] = df.claim.replace(to_replace=['Claim ID: ' + e for e in list_old], value=['Claim ID: ' + e for e in list_new], regex=True)
df['new_description'] = df.description.replace(to_replace=['\* ' + e + '\\n' for e in list_old], value=['* ' + e + '\\n' for e in list_new], regex=True)
产生以下输出: