我必须在另外两个数据库中选择前5行,并对每个数据库列进行排序。
这是我的代码。
SELECT TOP 5 DK.dbo.TIME.TIME_STRT, DB1.dbo.DATA.PLC_11
FROM DK.dbo.TIME, DB1.dbo.DATA
ORDER BY TIME_STRT DESC, PLC_11 desc;
它已经运行了10分钟。
+ edit
我想我做了一个奇怪的解释
DB1.dbo.DATA
PLC_TIME PLC_11
2019-11-24 23:25:48.443 110
2019-11-24 23:25:49.460 191
2019-11-24 23:25:57.037 599
2019-11-24 23:26:49.473 110
2019-11-24 23:26:50.490 195
2019-11-24 23:28:06.547 600
2019-11-24 23:28:36.720 109
2019-11-24 23:28:37.733 201
2019-11-24 23:29:06.553 600
2019-11-24 23:24:47.413 110
2019-11-24 23:24:48.437 186
2019-11-24 23:24:57.027 599
2019-11-24 23:29:37.747 109
2019-11-24 23:29:38.760 204
2019-11-24 23:30:06.570 600
2019-11-24 23:30:38.777 109
2019-11-24 23:30:39.793 210
2019-11-24 23:31:06.560 600
2019-11-24 23:31:39.817 109
2019-11-24 23:31:40.850 213
DK.dbo.TIME
TIME_STRT TIME_CODE
2020-03-11 08:20:48.000 11619
2020-03-11 09:45:36.000 11608
2020-03-11 07:27:21.587 11616
2020-03-11 13:38:08.000 11672
2020-03-11 07:36:18.000 11627
2020-03-11 08:19:15.000 11629
2020-03-11 07:05:41.000 11626
2020-03-11 10:15:45.000 11609
2020-03-11 06:48:45.000 11624
2020-03-11 13:31:12.000 11669
2020-03-11 16:30:43.000 11685
2020-03-11 13:18:38.000 11671
2020-03-11 14:30:05.000 11684
2020-03-11 13:20:50.000 11645
2020-03-11 14:07:31.000 11683
2020-03-11 13:07:21.090 11673
2020-03-11 15:20:20.000 11663
2020-03-11 14:30:43.000 11662
2020-03-11 14:10:01.000 11661
2020-03-11 13:00:23.000 11647
我想要这个结果。
2020-03-11 16:30:43.000 600
2020-03-11 15:20:20.000 600
2020-03-11 14:30:43.000 600
2020-03-11 14:30:05.000 600
2020-03-11 14:10:01.000 599
这两个数据库和表不相关。
SELECT t.TIME_STRT, p.PLC_11
FROM
(
SELECT TOP (5)
TIME_STRT
, TIME_CODE
, ROW_NUMBER() OVER(ORDER BY TIME_CODE DESC) AS ROW_NUMBER
FROM TIME
) t
INNER JOIN
(
SELECT TOP (5)
PLC_TIME
, PLC_11
, ROW_NUMBER() OVER(ORDER BY PLC_11 DESC) AS ROW_NUMBER
FROM DATA
) p
ON t.ROW_NUMBER = p.ROW_NUMBER
哪个会产生您想要的结果。
TIME_STRT PLC_11
2020-03-11 16:30:43.000 600
2020-03-11 15:20:20.000 600
2020-03-11 14:30:43.000 600
2020-03-11 14:30:05.000 600
2020-03-11 14:10:01.000 599
这里是dbfiddle,正在运行中。