AppleScript - 获取当前 iTunes 曲目的完整信息

Question

我正在尝试返回我的计算机上正在播放的当前 iTunes 曲目的信息。

我可以获得这样的单一信息：

tell application "iTunes"
get name of current track
end tell

例如，这会返回

Thunderstruck

。

但是我是否可以获取当前曲目的更多信息，以便它返回如下内容：

"AC/DC, Thunderstruck, Iron Man 2"

这可能吗？或者我必须创建多个脚本吗？

谢谢

Answer 1

要获得

name

、

artist

和

album

tell application "iTunes"
    get {name, artist, album} of current track
end tell

结果是一个列表

---

得到一切

tell application "iTunes"
    get properties of current track
end tell

结果创纪录

Answer 2

如果您使用 JXA，则：

• 获取 JavaScript 对象形式的轨道属性：

// File: GetTrackInfo.jxa
const appMusic = Application("com.apple.Music");
const currentTrack = appMusic.currentTrack();
const properties = currentTrack.properties()
// Get track info as a JSON
console.log(JSON.stringify(properties, null, 2))
// Get certain track info property.
console.log(properties.name)

• 获取单轨属性：

// File: GetTrackInfoAndCopyToClipboard.jxa
const currentApp = Application.currentApplication();
currentApp.includeStandardAdditions = true;

const appMusic = Application("com.apple.Music");
const currentTrack = appMusic.currentTrack();
const result = `${currentTrack.artist()} - ${currentTrack.name()} @ ${currentTrack.album()}`;
console.log(`Result: ${result}`);

// Bonus, copying track into into Clipboard and sending notification.
currentApp.setTheClipboardTo(result);
currentApp.displayNotification(result);