我想跳过除first_name,node100及其子代之外的所有节点。我有这个XML(实际上我有很多员工,每个员工标签都有很多节点):
<employees>
<employee>
<first_name>John</first_name>
<last_name>Doe</last_name>
<age>26</age>
</employee>
<employee>
<first_name>Peter</first_name>
<last_name>Parker</last_name>
<age>30</age>
</employee>
</employees>
我能够使用Jackson的FasterXML进行阅读。我创建了2个POJOS来映射上面的XML结构
@JacksonXmlRootElement(localName = "employees") public final class Employees {
@JacksonXmlElementWrapper(localName = "employee", useWrapping = false)
private Employee[] employee;
//ommiteed getter and setters
public final class Employee {
@JacksonXmlProperty(localName = "id", isAttribute = true)
private String id;
@JacksonXmlProperty(localName = "first_name")
private String firstName;
@JacksonXmlProperty(localName = "last_name")
private String lastName;
@JacksonXmlProperty(localName = "age")
private int age;
现在在生产中,xml节点内有1000s个节点
<employee>
<first_name>John</first_name>
<last_name>Doe</last_name>
<age>26</age>
<node1> </node1>
<node2> </node2>
..
<node100>
<values>
<value> val1 </value>
<value> val1 </value>
<value> val1 </value>
<value> val1 </value>
</node100>
</employee>
<node100> is also inside 4-5 nodes (which i have not shown above).
所以,我的问题是如何只读取first_name,last_name和tag。我的POJO类的结构应该是什么?
将XML转换为POJO的代码
System.out.println( " hello");
ObjectMapper objectMapper = new XmlMapper();
// Reads from XML and converts to POJO
Employees employees = objectMapper.readValue(
StringUtils.toEncodedString(Files.readAllBytes(Paths.get("C:\\Users\\91895\\Downloads\\File\\XmlFile.xml")), StandardCharsets.UTF_8),
Employees.class);
System.out.println(employees);
在您的类中,定义要从XML读取的元素。要忽略其他元素,请相应地配置ObjectMapper: