SQL Server中字符串的单引号

Question

DECLARE @rpmProvider varchar(200) = 'Prudhvi, raj,Lalith, Kumar';

DECLARE @xml xml
DECLARE @XMT_TEXT AS VARCHAR(200)

SET @XMT_TEXT = REPLACE(REPLACE(REPLACE(''''+ @rpmProvider + '''', ', ', '|'), ',', '</X><X>'), '|', ', ')
SET @xml = cast(('<X>' + @XMT_TEXT + '</X>') as xml)


SELECT N.value('.', 'varchar(50)') as value
FROM @xml.nodes('X') as T(N);

我的输出：

1. 'Prudhvi, raj
2. Lalith, Kumar'

预期产量：

1. 'Prudhvi, raj'
2. 'Lalith, Kumar'

Answer 1

尝试如下

 DECLARE @rpmProvider varchar(200) = 'Prudhvi, raj,Lalith, Kumar';

DECLARE @xml xml
DECLARE @XMT_TEXT AS VARCHAR(200)

SET @XMT_TEXT = REPLACE(REPLACE(REPLACE(''''+ @rpmProvider + '''', ', ', '|'), ',', '</X><X>'), '|', ', ')
SET @xml = cast(('<X>' + @XMT_TEXT + '</X>') as xml)


SELECT case when left( N.value('.', 'varchar(50)'),1)=''''  then '' else
'''' end + N.value('.', 'varchar(50)')  +
case when right( N.value('.', 'varchar(50)'),1)=''''  then '' else
'''' end as value
FROM @xml.nodes('X') as T(N);



 value
'Prudhvi, raj'
'Lalith, Kumar'

demo link

Answer 2

如果删除与XML相关的所有代码，请离开

DECLARE @rpmProvider varchar(200) = 'Prudhvi, raj,Lalith, Kumar';
select REPLACE(REPLACE(REPLACE(''''+ @rpmProvider + '''', ', ', '|'), ',', '</X><X>'), '|', ', ') 

你会看到周围没有引号。结果是

'Prudhvi, raj</X><X>Lalith, Kumar'

您可以通过将替换字符串更改为''</X><X>''来解决此问题，在标记之前和之后使用两个单引号：

select REPLACE(REPLACE(REPLACE(''''+ @rpmProvider + '''', ', ', '|'), ',', '''</X><X>'''), '|', ', ')

结果现在是：

'Prudhvi, raj'</X><X>'Lalith, Kumar'

这段代码非常脆弱。它取决于空格来分隔键，值和对。 SQL（语言）在字符串解析和操作方面非常弱。这种解析应该在数据存储在数据库之前完成。

Answer 3

您可以尝试以下查询，

DECLARE @rpmProvider varchar(200) = 'Prudhvi, raj,Lalith, Kumar';

DECLARE @xml xml
DECLARE @XMT_TEXT AS VARCHAR(200)

SET @XMT_TEXT = REPLACE(REPLACE(REPLACE(''''+ @rpmProvider + '''', ', ', '|'), ',', '''</X><X>'''), '|', ', ')
SET @xml = cast(('<X>' + @XMT_TEXT + '</X>') as xml)


SELECT N.value('.', 'varchar(50)') as value
FROM @xml.nodes('X') as T(N);

Answer 4

试试这个

DECLARE @rpmProvider varchar(200) = 'Prudhvi, raj,Lalith, Kumar';

DECLARE @xml xml
DECLARE @XMT_TEXT AS VARCHAR(200)

SET @XMT_TEXT = REPLACE(REPLACE(REPLACE( @rpmProvider , ', ', '|'), ',', '</X><X>'), '|', ', ')

SET @xml = cast(('<X>' + @XMT_TEXT + '</X>') as xml)


SELECT ''''+N.value('.', 'varchar(50)')+'''' as value
FROM @xml.nodes('X') as T(N);