使用gtk2创建和存储图像?

问题描述 投票:0回答:1

我在使用gtk2绘制图像时遇到了一些麻烦。我试过这段代码:

#include <gtk/gtk.h>

static gboolean button_press_callback (GtkWidget *event_box, GdkEventButton *event, gpointer data)
{
  g_print ("Event box clicked at coordinates %f,%f\n",
           event->x, event->y);

  /* Returning TRUE means we handled the event, so the signal
   * emission should be stopped (don't call any further
   * callbacks that may be connected). Return FALSE
   * to continue invoking callbacks.
   */
  return TRUE;
}

static GtkWidget*
create_image (void)
{
  GtkWidget *image;
  GtkWidget *event_box;

  image = gtk_image_new_from_file ("image.png");
}

int main(int argc, char const *argv[])
{
  create_image();
  return 0;
}

它不会在屏幕上绘制任何图像,事实上我根本看不到任何窗口。另外,将图像存储在变量中以备将来使用的最佳方法是什么?

c gtk gtk2
1个回答
1
投票

我建议你看看gtk教程https://developer.gnome.org/gtk-tutorial/stable/,你的代码中缺少很多东西,在这里显示如何在窗口中显示简单图片的示例:

#include <gtk/gtk.h>

GtkWidget* create_gui()
{
    GtkWidget *win = gtk_window_new(GTK_WINDOW_TOPLEVEL); // create the application window
    GtkWidget *img = gtk_image_new_from_file("image.png"); // image shall be in the same dir 
    gtk_container_add(GTK_CONTAINER(win), img); // add the image to the window
    g_signal_connect(G_OBJECT(win), "destroy", G_CALLBACK(gtk_main_quit), NULL); // end the application if user close the window
    return win;
}
int main(int argc, char** argv) {
    GtkWidget* win;

    gtk_init(&argc, &argv);


    win = create_gui();
    gtk_widget_show_all(win); // display the window
    gtk_main(); // start the event loop
    return 0;
}

BTW,gtk 2不再被维护,我建议你从gtk3开始,如果可以的话

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