如何使用 python selenium 处理弹出网站

Question

我正在从多个网站获取数据，并且遇到了一个弹出窗口的网站（见下图）。我尝试了多种方法，例如检查警报或获取驾驶员的车窗，以便我可以切换到它并关闭它。我真的很困惑，似乎找不到解决办法。我见过解决方案，但这些解决方案带有警报。有人有想法吗？

Answer 1

在 Selenium 中，您可以指定等待给定元素，因此如果这是已知的弹出窗口，则：

1. 在此弹出窗口中选择元素
2. 等待该元素被检测到
3. 导航至十字按钮并关闭弹出窗口

Answer 2

我尝试了多种方法。所有这些都成功了，因为我在

time.sleep(10)

之后添加了

driver.get('url')

。

from selenium import webdriver
import time
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By


driver = webdriver.Chrome(executable_path="path to chromedriver.exe")
driver.maximize_window()
driver.implicitly_wait(30)
driver.get("https://satellitenewsnetwork.com/")
time.sleep(10) # None of the below method works if this is removed.
wait = WebDriverWait(driver,30)

driver.switch_to.frame(driver.find_element_by_id("ml-webforms-popup-2207054"))
# First:
closepopup = driver.find_element_by_xpath("//div[@class='mailerlite-popup']/a")
print(closepopup.get_attribute("class"))
closepopup.click()

# Second:
# popup = wait.until(EC.presence_of_element_located((By.XPATH,"//div[@class='mailerlite-popup']"))) # Tried with visibility_of_element_located too.
# print(popup.get_attribute("class"))
# closepopup = driver.find_element_by_xpath("//div[@class='mailerlite-popup']/a")
# print(closepopup.get_attribute("class"))
# closepopup.click()

# Third:
# closepopup = driver.find_element_by_xpath("//div[@class='mailerlite-popup']/a")
# print(closepopup.get_attribute("class"))
# driver.execute_script("arguments[0].click();",closepopup)
#
# Fourth:
# closepopup = driver.find_element_by_xpath("//div[@class='mailerlite-popup']/a")
# print(closepopup.get_attribute("class"))
# ActionChains(driver).move_to_element(closepopup).click().perform()

time.sleep(5)

driver.quit()

Answer 3

2年零4个月了仍然没有人找到答案还是什么！！ ，我也陷入这样的问题