我有一个在对象侧面定义的功能。我已经使用Qunit编写测试用例。当我尝试生成代码覆盖率报告时,它给了我错误,未定义var测试。
JS文件
$(function(){
var obj = {
convertPostCode: function (postcode) {
var len = postcode.length,
index = 0;
switch (len) {
case 5:
index = 2;
break;
case 6:
index = 3;
break;
case 7:
index = 4;
break;
default:
break;
}
return postcode.substr(0, index) + " " + postcode.substr(index);
}
}
});
Qunit测试用例
QUnit.test("convertPostCodeFromat", function (assert) {
var postcode;
postcode = "HA11PQ";
assert.equal(obj.convertPostCode(postcode), "HA1 1PQ", "Postcode is " + postcode + ". Returns - " + obj.convertPostCode(postcode) + ". We expect return true");
});
首先$是jquery,将第一个参数视为选择器,但仍执行该函数,但返回一个jquery对象。
其次,obj是在该函数范围内定义的,在您的测试范围内将不可用。
[使其可用,在与测试相同的级别或比测试高的一个或多个级别之外定义obj,然后在$内部的函数内设置其值
示例
var obj;
$(function(){
obj = {
convertPostCode: function (postcode) {
var len = postcode.length,
index = 0;
switch (len) {
case 5:
index = 2;
break;
case 6:
index = 3;
break;
case 7:
index = 4;
break;
default:
break;
}
return postcode.substr(0, index) + " " + postcode.substr(index);
}
}
});
假设测试处于同一级别,那么您现在应该可以访问obj