从IEnumerator函数实例获取参数值

Question

假设我有一个IEnumerator的列表：

public List<IEnumerator> routines;

假设我有这个枚举：

public enum Shape { CIRCLE, TRIANGLE, SQUARE }

[我有很多IEnumerator例程都将Shape作为参数：

public IEnumerator Move(Shape shape, float distance){ /* code */ }
public IEnumerator Jump(Shape shape, float height){ /* code */ }
public IEnumerator Fire(Shape shape, float power){ /* code */ }

我的列表routines将包含这些功能的一系列实例（稍后将在StartCoroutine中调用：]

routines.Add(Move(Shape.SQUARE, 1));
routines.Add(Jump(Shape.CIRCLE, 1));
routines.Add(Fire(Shape.TRIANGLE, 1));
//...

鉴于我已经用所有这些函数填充了routines，是否有办法让我遍历routines并找出每个函数调用的Shape参数？在这种情况下，它将是SQUARE，CIRCLE，TRIANGLE等。

Answer 1

如果您的枚举器实现了解“形状”，则可以从routines中投射项目并获得形状。

public interface IShapedEnumerator : IEnumerator {
  Shape EnumeratorShape {get; }
}

pblic class ShapedIteratorProxy : IShapedEnumerator {
  private readonly IEnumerator _baseEnumerator;
  private readonly Shape _shape;
  public Shape EnumeratorShape => _shape;

  public ShapedIteratorProxy (Shape shape, IEnumerator baseEnumerator) {
    _baseEnumerator = baseEnumerator;
    _shape = shape;
  }

  public ShapedIteratorProxy (Shape shape, float arg, Func<Shape, float, IEnumerator> operation)
    : this(shape, operation(shape, arg)) 
  {}
  // implementation of IEnumerator that proxy all calls to _baseEnumerator.
  // ...
}

routines.Add(new ShapedIteratorProxy(Shape.SQUARE, Move(Shape.SQUARE, 1)));
routines.Add(new ShapedIteratorProxy(Shape.CIRCLE, 1, Jump);
routines.Add(new ShapedIteratorProxy(Shape.TRIANGLE, 1, Fire);

var shapes = routines.OfType<IShapedEnumerator>()
                     .Select(s=>s.EnumeratorShape)
                     .ToArray();

请注意，如果routines包含未实现IShapedEnumerator的项目，则将跳过它们。