[HDF5 in python:读取文件

问题描述 投票:1回答:1

我以前没用过这个,但是突然不起作用:

import scipy.io
import numpy as np
import h5py
f = h5py.File('Dv25.mat','r')
D = f["Dv25"]

输出:

Traceback (most recent call last):

  File "C:/Users/jonathan/Documents/Forskning/P1/Datab/Felles/Matart/Felles/datab.py", line 5, in 
<module>
    D = f["Dv25"]
  File "h5py\_objects.pyx", line 54, in h5py._objects.with_phil.wrapper
  File "h5py\_objects.pyx", line 55, in h5py._objects.with_phil.wrapper
  File "C:\Program Files\Python38\lib\site-packages\h5py\_hl\group.py", line 264, in __getitem__
    oid = h5o.open(self.id, self._e(name), lapl=self._lapl)
  File "h5py\_objects.pyx", line 54, in h5py._objects.with_phil.wrapper
  File "h5py\_objects.pyx", line 55, in h5py._objects.with_phil.wrapper
  File "h5py\h5o.pyx", line 190, in h5py.h5o.open
KeyError: "Unable to open object (object 'Dv25' doesn't exist)"

但是,键入f给出:

>>> f
<HDF5 file "Dv25.mat" (mode r)>

并且将Dv25.mat交换为Dv25或使用'或'都没有帮助。

此问题的原因是什么,如何解决?显然,此文件是“那里”

谢谢!

Best,J

python hdf5 h5py
1个回答
0
投票

一些h5py / HDF5基础知识:f是文件对象。f['Dv25']是对象引用(组或数据集)。在这种情况下,它是根级别('/')名为“ Dv25”的节点。显然,此文件中不存在使用该名称的对象。使用f.keys()在根级别获取对象。这将返回根对象的视图;它们可以是组或数据集。您可以遍历它们以获取名称。要打印,请使用以下循环:(应标识根级别名称):

for i in f.keys():  
    print (i)

注:.mat扩展名通常来自Matlab,该扩展名具有写入HDF5格式文件的选项。确保以这种格式编写。

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